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Ch.2 - Atoms, Molecules, and Ions
Brown - Chemistry: The Central Science 15th Edition
Brown15th EditionChemistry: The Central ScienceISBN: 9780137542970Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 13a2

A chemist finds that 30.82 g of nitrogen will react with 17.60, 35.20, 70.40, or 88.00 g of oxygen to form four different compounds. (a) Calculate the mass of oxygen per gram of nitrogen in each compound. 30.82 g N and 35.20 g O

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Identify the given masses of nitrogen and oxygen: 30.82 g of nitrogen and 35.20 g of oxygen.
Understand that you need to find the mass of oxygen per gram of nitrogen for the given compound.
Set up the ratio of the mass of oxygen to the mass of nitrogen: \( \frac{\text{mass of oxygen}}{\text{mass of nitrogen}} = \frac{35.20 \text{ g}}{30.82 \text{ g}} \).
Simplify the ratio to find the mass of oxygen per gram of nitrogen.
Express the simplified ratio as the mass of oxygen per 1 gram of nitrogen.

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Stoichiometry

Stoichiometry is the branch of chemistry that deals with the quantitative relationships between the reactants and products in a chemical reaction. It allows chemists to calculate the amounts of substances consumed and produced in a reaction based on balanced chemical equations. Understanding stoichiometry is essential for determining how much oxygen reacts with a given mass of nitrogen in this scenario.
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Stoichiometry Concept

Mass Ratio

The mass ratio is a comparison of the mass of one substance to the mass of another substance in a chemical reaction. In this case, calculating the mass of oxygen per gram of nitrogen involves finding the ratio of the mass of oxygen to the mass of nitrogen. This concept is crucial for understanding how different compounds can form from varying amounts of reactants.
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Neutron-Proton Ratio

Chemical Compounds

Chemical compounds are substances formed when two or more elements chemically bond together in fixed proportions. The different masses of oxygen reacting with a constant mass of nitrogen indicate the formation of different compounds, which can have distinct properties. Recognizing how these compounds differ based on their elemental composition is key to interpreting the results of the reaction.
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Chemical Properties
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A chemist finds that 30.82 g of nitrogen will react with 17.60, 35.20, 70.40, or 88.00 g of oxygen to form four different compounds. (b) How do the numbers in part (a) support Dalton's atomic theory?

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A chemist finds that 30.82 g of nitrogen will react with 17.60, 35.20, 70.40, or 88.00 g of oxygen to form four different compounds. (a) Calculate the mass of oxygen per gram of nitrogen in each compound. 30.82 g N and 70.40 g O

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A chemist finds that 30.82 g of nitrogen will react with 17.60, 35.20, 70.40, or 88.00 g of oxygen to form four different compounds. (a) Calculate the mass of oxygen per gram of nitrogen in each compound. 30.82 g N and 17.60 g O

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Domanda del libro di testo

A chemist finds that 30.82 g of nitrogen will react with 17.60, 35.20, 70.40, or 88.00 g of oxygen to form four different compounds. (a) Calculate the mass of oxygen per gram of nitrogen in each compound. 30.82 g N and 88.00 g O

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