Skip to main content
Ch.6 - Electronic Structure of Atoms
Brown - Chemistry: The Central Science 15th Edition
Brown15th EditionChemistry: The Central ScienceISBN: 9780137542970Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoBrown 15th EditionCh.6 - Electronic Structure of AtomsProblema 33a
Capitolo 6, Problema 33a

Molybdenum metal must absorb radiation with a minimum frequency of 1.09 * 1015 s - 1 before it can eject an electron from its surface via the photoelectric effect. (a) What is the minimum energy needed to eject an electron?

Guida verificata passo dopo passo
1
Identify the relationship between energy and frequency using the equation: \( E = h \nu \), where \( E \) is the energy, \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \text{ J s} \)), and \( \nu \) is the frequency.
Substitute the given frequency \( \nu = 1.09 \times 10^{15} \text{ s}^{-1} \) into the equation.
Calculate the energy \( E \) by multiplying Planck's constant \( h \) with the frequency \( \nu \).
Ensure the units are consistent, with energy in joules (J).
Interpret the result as the minimum energy required to eject an electron from the surface of molybdenum.

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
1m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Photoelectric Effect

The photoelectric effect is a phenomenon where electrons are emitted from a material when it absorbs light or electromagnetic radiation. This effect demonstrates the particle nature of light, as photons must have sufficient energy to overcome the work function of the material to eject electrons. The minimum frequency of radiation required to cause this emission is directly related to the energy of the incoming photons.
Video consigliato:
Percorso guidato
02:31
Photoelectric Effect

Energy-Frequency Relationship

The energy of a photon is directly proportional to its frequency, described by the equation E = hν, where E is energy, h is Planck's constant (6.626 x 10^-34 J·s), and ν is the frequency of the radiation. This relationship allows us to calculate the energy associated with a specific frequency of light, which is crucial for determining the minimum energy needed to eject an electron in the photoelectric effect.
Video consigliato:
Percorso guidato
00:31
Frequency-Wavelength Relationship

Planck's Constant

Planck's constant is a fundamental constant in quantum mechanics that relates the energy of a photon to its frequency. It has a value of approximately 6.626 x 10^-34 J·s. Understanding this constant is essential for calculations involving the energy of photons, particularly in the context of the photoelectric effect, where it helps determine the energy required to eject electrons from a material.
Video consigliato:
Percorso guidato
00:50
Photons and Planck's Constant
Pratica correlata
Domanda del libro di testo

A stellar object is emitting radiation at 3.55 mm. a. What type of electromagnetic spectrum is this radiation? b. If a detector is capturing 3.2×108 photons per second at this wavelength, what is the total energy of the photons detected in 1.0 hour?

2
views
Domanda del libro di testo

Molybdenum metal must absorb radiation with a minimum frequency of 1.09 * 1015 s - 1 before it can eject an electron from its surface via the photoelectric effect. (b) What wavelength of radiation will provide a photon of this energy?

4
views
Domanda del libro di testo

Molybdenum metal must absorb radiation with a minimum frequency of 1.09 * 1015 s - 1 before it can eject an electron from its surface via the photoelectric effect. (c) If molybdenum is irradiated with light of wavelength of 120 nm, what is the maximum possible kinetic energy of the emitted electrons?

2
views
Domanda del libro di testo

A diode laser emits at a wavelength of 987 nm. (a) In what portion of the electromagnetic spectrum is this radiation found? (b) All of its output energy is absorbed in a detector that measures a total energy of 0.52 J over a period of 32 s. How many photons per second are being emitted by the laser?

934
views
Domanda del libro di testo

The energy from radiation can be used to cause the rupture of chemical bonds. A minimum energy of 242 kJ/mol is required to break the chlorine–chlorine bond in Cl2. What is the longest wavelength of radiation that possesses the necessary energy to break the bond? What type of electromagnetic radiation is this?

2
views