Domanda del libro di testo
Iron metal can be produced from the mineral hematite, Fe2O3, by reaction with carbon. How many kilograms of iron are present in 105 kg of hematite?
800
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Ch.3 - Mass Relationships in Chemical Reactions
McMurry8th EditionChemistryISBN: 9781292336145
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TOC.tableOfContents
- Ch.1 - Chemical Tools: Experimentation & Measurement170
- Ch.2 - Atoms, Molecules & Ions160
- Ch.3 - Mass Relationships in Chemical Reactions169
- Ch.4 - Reactions in Aqueous Solution199
- Ch.5 - Periodicity & Electronic Structure of Atoms102
- Ch.6 - Ionic Compounds: Periodic Trends and Bonding Theory92
- Ch.7 - Covalent Bonding and Electron-Dot Structures61
- Ch.8 - Covalent Compounds: Bonding Theories and Molecular Structure59
- Ch.9 - Thermochemistry: Chemical Energy122
- Ch.10 - Gases: Their Properties & Behavior155
- Ch.11 - Liquids & Phase Changes54
- Ch.12 - Solids and Solid-State Materials73
- Ch.13 - Solutions & Their Properties120
- Ch.14 - Chemical Kinetics98
- Ch.15 - Chemical Equilibrium125
- Ch.16 - Aqueous Equilibria: Acids & Bases110
- Ch.17 - Applications of Aqueous Equilibria147
- Ch.18 - Thermodynamics: Entropy, Free Energy & Equilibrium86
- Ch.19 - Electrochemistry154
- Ch.20 - Nuclear Chemistry96
- Ch.21 - Transition Elements and Coordination Chemistry156
- Ch.22 - The Main Group Elements187
- Ch.23 - Organic and Biological Chemistry51
Capitolo 3, Problema 59
A sample that weighs 107.75 g is a mixture of 30% helium atoms and 70% krypton atoms. How many particles are present in the sample?
Guida verificata passo dopo passo1
Determine the mass of helium in the sample by multiplying the total mass by the percentage of helium: \( \text{mass of He} = 107.75 \text{ g} \times 0.30 \).
Determine the mass of krypton in the sample by multiplying the total mass by the percentage of krypton: \( \text{mass of Kr} = 107.75 \text{ g} \times 0.70 \).
Calculate the number of moles of helium using its molar mass (4.00 g/mol): \( \text{moles of He} = \frac{\text{mass of He}}{4.00 \text{ g/mol}} \).
Calculate the number of moles of krypton using its molar mass (83.80 g/mol): \( \text{moles of Kr} = \frac{\text{mass of Kr}}{83.80 \text{ g/mol}} \).
Use Avogadro's number (\(6.022 \times 10^{23}\) particles/mol) to find the total number of particles: \( \text{total particles} = (\text{moles of He} + \text{moles of Kr}) \times 6.022 \times 10^{23} \).
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Molar Mass
Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). For helium, the molar mass is approximately 4.00 g/mol, while for krypton, it is about 83.80 g/mol. Understanding molar mass is essential for converting between grams and moles, which is necessary for calculating the number of particles in a sample.
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Percorso guidato
02:11
Molar Mass Concept
Avogadro's Number
Avogadro's number, approximately 6.022 x 10²³, is the number of particles (atoms, molecules, etc.) in one mole of a substance. This constant allows chemists to relate the mass of a substance to the number of particles it contains. In this problem, it will be used to determine the total number of helium and krypton atoms in the mixture after calculating the moles of each gas.
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Percorso guidato
02:11Avogadro's Law
Percentage Composition
Percentage composition refers to the mass percentage of each component in a mixture. In this case, the sample consists of 30% helium and 70% krypton by mass. This information is crucial for determining the mass of each gas in the sample, which is then used to calculate the number of moles and ultimately the total number of particles present.
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Percorso guidato
04:19Matter Composition
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In the preparation of iron from hematite, Fe2O3 reacts with carbon:
Fe2O3 + C --> Fe + CO2 Unbalanced
(a) Balance the equation.
(b) How many moles of carbon are needed to react with 525 g of hematite?
(c) How many grams of carbon are needed to react with 525 g of hematite?
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