How many milliliters of a 0.45 M BaCl₂ solution contain 15.0 g of BaCl₂?

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Calculate the molar mass of \( \text{BaCl}_2 \) by adding the atomic masses of barium (Ba) and chlorine (Cl).

Convert the given mass of \( \text{BaCl}_2 \) (15.0 g) to moles using the formula: \( \text{moles} = \frac{\text{mass}}{\text{molar mass}} \).

Use the molarity formula \( M = \frac{\text{moles of solute}}{\text{liters of solution}} \) to find the volume of the solution in liters. Rearrange the formula to solve for volume: \( \text{volume} = \frac{\text{moles of solute}}{M} \).

Convert the volume from liters to milliliters by multiplying by 1000, since 1 liter = 1000 milliliters.

Ensure all units are consistent and check calculations for accuracy.

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Molarity (M)

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is expressed in moles per liter (mol/L). Understanding molarity is essential for converting between mass of a solute and volume of a solution, as it allows us to relate the amount of substance to its concentration in a given volume.

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00:53

Molarity Concept

Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). For BaCl2, the molar mass can be calculated by summing the atomic masses of barium (Ba) and chlorine (Cl). This concept is crucial for converting grams of a compound to moles, which is necessary for using the molarity in calculations.

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Molar Mass Concept

Stoichiometry

Stoichiometry involves the calculation of reactants and products in chemical reactions based on the conservation of mass. It allows us to use the relationships between moles, mass, and volume to solve problems involving solutions. In this context, stoichiometry helps determine how much volume of a solution is needed to contain a specific mass of solute.

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