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Ch.10 - Chemical Bonding II: Molecular Shapes & Valence Bond Theory
Tro - Chemistry: A Molecular Approach 4th Edition
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Capitolo 10, Problema 60

Which hybridization scheme allows the central atom to form more than four bonds? sp3, sp3d, sp2

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Identify the hybridization schemes given: \(sp^3\), \(sp^3d\), and \(sp^2\).
Understand that \(sp^3\) hybridization involves one s orbital and three p orbitals, allowing for a maximum of four bonds.
Recognize that \(sp^2\) hybridization involves one s orbital and two p orbitals, allowing for a maximum of three bonds.
Consider \(sp^3d\) hybridization, which involves one s orbital, three p orbitals, and one d orbital, allowing for more than four bonds.
Conclude that \(sp^3d\) hybridization allows the central atom to form more than four bonds, typically up to five bonds.

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Hybridization

Hybridization is a concept in chemistry that describes the mixing of atomic orbitals to form new hybrid orbitals. These hybrid orbitals can accommodate the bonding requirements of a central atom, allowing it to form covalent bonds with surrounding atoms. The type of hybridization (e.g., sp, sp2, sp3) determines the geometry and number of bonds that can be formed.
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Hybridization

Types of Hybridization

Different types of hybridization correspond to different bonding scenarios. For example, sp3 hybridization involves one s and three p orbitals, allowing for four equivalent bonds, typically seen in tetrahedral geometries. In contrast, sp3d hybridization includes one s, three p, and one d orbital, enabling the formation of five bonds, as seen in trigonal bipyramidal geometries.
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Hybridization

Coordination Number

The coordination number refers to the number of bonds formed by a central atom in a molecule. It is crucial for understanding the hybridization scheme, as a higher coordination number indicates the ability to form more bonds. For instance, a central atom with sp3d hybridization can achieve a coordination number of five, allowing it to bond with five other atoms.
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Coordination Numbers
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