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Ch.13 - Solutions
Tro - Chemistry: A Molecular Approach 4th Edition
Tro4th EditionChemistry: A Molecular ApproachISBN: 9780134112831Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoTro 4th EditionCh.13 - SolutionsProblema 54
Capitolo 13, Problema 54

To what volume should you dilute 125 mL of an 8.00 M CuCl2 solution so that 50.0 mL of the diluted solution contains 4.67 g of CuCl2?

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Calculate the moles of CuCl2 in 50.0 mL of the diluted solution using the given mass (4.67 g) and the molar mass of CuCl2.
Determine the molarity of the diluted solution by dividing the moles of CuCl2 by the volume of the diluted solution in liters (50.0 mL converted to liters).
Use the dilution equation, M1V1 = M2V2, where M1 and V1 are the initial molarity and volume, and M2 and V2 are the molarity and volume of the diluted solution, respectively.
Substitute the known values into the dilution equation: M1 = 8.00 M, V1 = 125 mL, and M2 is the molarity calculated in step 2.
Solve for V2, the total volume of the diluted solution, ensuring that all volumes are in the same units (liters or milliliters).

Concetti chiave

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Molarity (M)

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is expressed in moles per liter (mol/L). Understanding molarity is crucial for dilutions and reactions, as it allows chemists to quantify how much solute is present in a given volume of solution.
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Molarity Concept

Dilution Equation

The dilution equation, often expressed as M1V1 = M2V2, relates the molarity and volume of a concentrated solution (M1 and V1) to the molarity and volume of the diluted solution (M2 and V2). This equation is essential for calculating how to achieve a desired concentration after dilution, making it a fundamental tool in laboratory practices.
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Percorso guidato
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Dilution Equation

Mass to Moles Conversion

To relate mass to moles, the formula used is n = m/M, where n is the number of moles, m is the mass of the substance, and M is the molar mass. This conversion is necessary when determining how much solute is present in a solution, especially when given in grams, and is vital for solving problems involving concentrations and dilutions.
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Percorso guidato
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Mass and Moles Conversion
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