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Ch.20 - Radioactivity and Nuclear Chemistry
Tro - Chemistry: A Molecular Approach 4th Edition
Tro4th EditionChemistry: A Molecular ApproachISBN: 9780134112831Non è quello che usi tu?Cambia libro di testo
Capitolo 20, Problema 78a

Complete each nuclear equation and calculate the energy change (in J/mol of reactant) associated with each (Al-27 = 26.981538 amu, Am-241 = 241.056822 amu, He-4 = 4.002603 amu, Np-237 = 237.048166 amu, P-30 = 29.981801 amu, S-32 = 31.972071 amu, and Si-29 = 28.976495 amu).
a. 2713Al + 42He → 3015P + ____

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Identify the missing product in the nuclear reaction. The sum of atomic numbers and mass numbers must be conserved. For the given reaction, \( ^{27}_{13}\text{Al} + ^{4}_{2}\text{He} \rightarrow ^{30}_{15}\text{P} + X \), solve for X.
Calculate the atomic number and mass number of the missing product. The atomic number should be \( 13 + 2 - 15 = 0 \) and the mass number should be \( 27 + 4 - 30 = 1 \). Therefore, the missing product is a neutron \( ^{1}_{0}\text{n} \).
Write the complete nuclear equation: \( ^{27}_{13}\text{Al} + ^{4}_{2}\text{He} \rightarrow ^{30}_{15}\text{P} + ^{1}_{0}\text{n} \).
Calculate the mass defect by finding the difference in mass between the reactants and products. Use the given atomic masses: \( \Delta m = (26.981538 + 4.002603) - (29.981801 + 1.008665) \) amu.
Convert the mass defect from amu to energy using Einstein's equation \( E = \Delta m \times c^2 \), where \( c \) is the speed of light \( 3.00 \times 10^8 \text{ m/s} \). Then, convert the energy from J to J/mol by multiplying by Avogadro's number \( 6.022 \times 10^{23} \text{ mol}^{-1} \).

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Nuclear reactions involve changes in an atom's nucleus and can result in the transformation of one element into another. These reactions are characterized by the conservation of mass and energy, where the total mass and energy before and after the reaction remain constant. Understanding the types of nuclear reactions, such as alpha decay, beta decay, and fusion, is essential for completing nuclear equations.
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