Skip to main content
Ch.7 - Quantum-Mechanical Model of the Atom
Tro - Chemistry: A Molecular Approach 4th Edition
Tro4th EditionChemistry: A Molecular ApproachISBN: 9780134112831Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 72

An electron in a hydrogen atom relaxes to the n = 4 level, emitting light of 114 THz. What is the value of n for the level in which the electron originated?

Guida verificata passo dopo passo
1
Step 1: Understand that the frequency of the light emitted when an electron relaxes from a higher energy level to a lower one in a hydrogen atom can be calculated using the Rydberg formula: \(\frac{1}{\lambda} = R_H \left(\frac{1}{n_1^2} - \frac{1}{n_2^2}\right)\), where \(\lambda\) is the wavelength of the light, \(R_H\) is the Rydberg constant for hydrogen (approximately 1.097 x \$10^7\( m\)^{-1}\(), \)n_1$ is the principal quantum number of the lower energy level, and $n_2$ is the principal quantum number of the higher energy level.
Step 2: Convert the frequency of the light to wavelength using the formula \(\lambda = \frac{c}{\nu}\), where \(c\) is the speed of light (approximately \(3.00 \times 10^8\) m/s) and \(\nu\) is the frequency of the light.
Step 3: Substitute the known values into the Rydberg formula and solve for \(n_2\). Remember that \(n_1\) is 4 (the level to which the electron relaxes) and \(\lambda\) is the value you calculated in the previous step.
Step 4: You will get a quadratic equation in terms of \(n_2\). Solve this quadratic equation to find the value of \(n_2\).
Step 5: The solution to the quadratic equation will give two possible values for \(n_2\). However, since \(n_2\) must be greater than \(n_1\) (because the electron is relaxing to the \(n_1\) level), choose the larger of the two solutions as the value of \(n_2\).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
9m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Energy Levels in Hydrogen Atom

In a hydrogen atom, electrons occupy discrete energy levels, denoted by quantum numbers (n). The energy levels are quantized, meaning electrons can only exist in specific states. The difference in energy between these levels determines the frequency of light emitted or absorbed when an electron transitions between them.
Video consigliato:
Percorso guidato
01:22
Hydrogenation Reactions

Frequency and Energy Relationship

The frequency of light emitted by an electron transitioning between energy levels is directly related to the energy difference between those levels. This relationship is described by the equation E = hν, where E is the energy difference, h is Planck's constant, and ν is the frequency of the emitted light. Thus, knowing the frequency allows us to calculate the energy change associated with the electron's transition.
Video consigliato:
Percorso guidato
00:31
Frequency-Wavelength Relationship

Rydberg Formula

The Rydberg formula provides a way to calculate the wavelengths (or frequencies) of light emitted during electron transitions in hydrogen. It is expressed as 1/λ = R_H(1/n1² - 1/n2²), where R_H is the Rydberg constant, n1 and n2 are the principal quantum numbers of the lower and upper energy levels, respectively. This formula is essential for determining the initial energy level (n) from which the electron transitioned.
Video consigliato:
Percorso guidato
02:26
Skeletal Formula
Pratica correlata
Domanda del libro di testo

The human eye contains a molecule called 11-cis-retinal that changes shape when struck with light of sufficient energy. The change in shape triggers a series of events that results in an electrical signal being sent to the brain that results in vision. The minimum energy required to change the conformation of 11-cis-retinal within the eye is about 164 kJ/mol. Calculate the longest wavelength visible to the human eye.

5687
views
2
comments
Domanda del libro di testo

An electron in the n = 7 level of the hydrogen atom relaxes to a lower-energy level, emitting light of 397 nm. What is the value of n for the level to which the electron relaxed?

8549
views
5
rank
2
comments
Domanda del libro di testo

An argon ion laser puts out 5.0 W of continuous power at a wavelength of 532 nm. The diameter of the laser beam is 5.5 mm. If the laser is pointed toward a pinhole with a diameter of 1.2 mm, how many photons travel through the pinhole per second? Assume that the light intensity is equally distributed throughout the entire cross-sectional area of the beam. (1 W = 1 J/s)

1009
views
Domanda del libro di testo

Calculate the frequency of the light emitted when an electron in a hydrogen atom makes each transition: a. n = 4 → n = 3 b. n = 5 → n = 1 c. n = 5 → n = 4 d. n = 6 → n = 5

8404
views
1
rank
Domanda del libro di testo

Ultraviolet radiation and radiation of shorter wavelengths can damage biological molecules because these kinds of radiation carry enough energy to break bonds within the molecules. A typical carbon–carbon bond requires 348 kJ/mol to break. What is the longest wavelength of radiation with enough energy to break carbon–carbon bonds?

3996
views
2
rank
Domanda del libro di testo

Calculate the wavelength of the light emitted when an electron in a hydrogen atom makes each transition and indicate the region of the electromagnetic spectrum (infrared, visible, ultraviolet, etc.) where the light is found. a. n = 2 → n = 1 b. n = 3 → n = 1 c. n = 4 → n = 2 d. n = 5 → n = 2

2102
views