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Ch.1 - Matter, Measurement & Problem Solving
Tro - Chemistry: A Molecular Approach 5th Edition
Tro5th EditionChemistry: A Molecular ApproachISBN: 9780134874371Non è quello che usi tu?Cambia libro di testo
Capitolo 1, Problema 117

The density of titanium is 4.51 g/cm3. What is the volume (in cubic inches) of 3.5 lb of titanium?

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Step 1: Convert the mass of titanium from pounds to grams. You can use the conversion factor 1 lb = 453.592 g.
Step 2: Use the given density to find the volume in cubic centimeters (cm^3). The formula for density is Density = Mass/Volume. Rearranging this formula gives Volume = Mass/Density.
Step 3: Substitute the mass in grams and the density in g/cm^3 into the formula to find the volume in cm^3.
Step 4: Convert the volume from cubic centimeters to cubic inches. You can use the conversion factor 1 in^3 = 16.387 cm^3.
Step 5: Substitute the volume in cm^3 into the conversion factor to find the volume in in^3.

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Concetti chiave

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Density

Density is defined as mass per unit volume, typically expressed in grams per cubic centimeter (g/cm³) in the metric system. It is a crucial property that helps determine how much space a given mass of a substance will occupy. In this question, the density of titanium allows us to relate its mass to its volume, which is essential for solving the problem.
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Density Concepts

Unit Conversion

Unit conversion is the process of converting a quantity expressed in one set of units to another. In this question, we need to convert the mass of titanium from pounds to grams and the volume from cubic centimeters to cubic inches. Understanding how to perform these conversions accurately is vital for obtaining the correct answer.
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Conversion Factors

Mass-Volume Relationship

The mass-volume relationship is a fundamental concept in chemistry that describes how mass and volume are interrelated through density. By using the formula density = mass/volume, we can rearrange it to find volume when mass and density are known. This relationship is key to solving the question, as it allows us to calculate the volume of titanium based on its mass and density.
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Relationship of Volume and Moles Example