Determine whether each transition in the hydrogen atom corresponds to absorption or emission of energy. a. n = 3 → n = 1 b. n = 2 → n = 4 c. n = 4 → n = 3
Ch.8 - The Quantum-Mechanical Model of the Atom
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Capitolo 8, Problema 69
Calculate the wavelength of the light emitted when an electron in a hydrogen atom makes each transition and indicate the region of the electromagnetic spectrum (infrared, visible, ultraviolet, etc.) where the light is found. a. n = 2 → n = 1 b. n = 3 → n = 1 c. n = 4 → n = 2 d. n = 5 → n = 2
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Identify the formula to calculate the wavelength of light emitted during an electron transition in a hydrogen atom: \( \frac{1}{\lambda} = R_H \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \), where \( R_H \) is the Rydberg constant (1.097 \(\times\) 10^7 \(\text{ m}\)^{-1}), \( n_1 \) is the lower energy level, and \( n_2 \) is the higher energy level.
For each transition, substitute the given values of \( n_1 \) and \( n_2 \) into the formula to find \( \frac{1}{\lambda} \).
Calculate \( \lambda \) by taking the reciprocal of \( \frac{1}{\lambda} \).
Convert the wavelength from meters to nanometers by multiplying by \( 10^9 \) (since 1 m = 10^9 nm).
Determine the region of the electromagnetic spectrum by comparing the calculated wavelength to known ranges: infrared (> 700 nm), visible (400-700 nm), ultraviolet (< 400 nm).

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Energy Levels in Hydrogen Atom
In a hydrogen atom, electrons occupy specific energy levels, denoted by quantum numbers (n). When an electron transitions between these levels, it either absorbs or emits energy in the form of light. The energy difference between the levels determines the wavelength of the emitted light, which can be calculated using the Rydberg formula.
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Hydrogenation Reactions
Wavelength and Frequency Relationship
The wavelength of light is inversely related to its frequency, as described by the equation c = λν, where c is the speed of light, λ is the wavelength, and ν is the frequency. This relationship is crucial for determining the wavelength of light emitted during electron transitions in the hydrogen atom, as the energy of the emitted photon can be calculated from the frequency.
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Frequency-Wavelength Relationship
Regions of the Electromagnetic Spectrum
The electromagnetic spectrum is divided into various regions based on wavelength and frequency, including infrared, visible, and ultraviolet light. The wavelength calculated from electron transitions in a hydrogen atom will fall into one of these regions, which helps in identifying the type of light emitted. For example, transitions from higher energy levels often result in ultraviolet light, while lower energy transitions may emit visible or infrared light.
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Electromagnetic Spectrum
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