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Given the mRNA sequence: aug ccg ucg auc cgg uaa, what is the corresponding polypeptide chain produced during translation?
A
Met-Pro-Ser-Ile-Arg
B
Met-Arg-Ile-Ser-Pro
C
Met-Pro-Leu-Ile-Gly
D
Met-Leu-Ser-Tyr-Gly
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1
Identify the codons in the mRNA sequence by dividing the sequence into groups of three nucleotides: aug, ccg, ucg, auc, cgg, and taa (stop codon).
Use the genetic code table to translate each codon into its corresponding amino acid. For example, 'aug' codes for Methionine (Met), which is the start codon.
Translate each subsequent codon: 'ccg' codes for Proline (Pro), 'ucg' codes for Serine (Ser), 'auc' codes for Isoleucine (Ile), and 'cgg' codes for Arginine (Arg).
Recognize that 'uaa' is a stop codon, signaling the end of translation and no amino acid is added for this codon.
Combine the amino acids in order to form the polypeptide chain: Met-Pro-Ser-Ile-Arg.