calculate-the-amount-of-excess-reactant-left-after-11-3-mol-zns-and-18-3-mol-o2-

Question

Calculate the amount of excess reactant left after 11.3 mol ZnS and 18.3 mol $$O_{2 }$$react according to the following reaction: 2 ZnS_{(s)} + 3 O_{2(g)}  → 2 ZnO_{(s)} + 2 SO_{2(g)}

Accepted Answer

1.35 mol

Answer

0 mol

Answer

0.65 mol

Answer

2.30 mol

Calculate the amount of excess reactant left after 11.3 mol ZnS and 18.3 mol O2 react according to the following reaction: 2 ZnS(s) + 3 O2(g) → 2 ZnO(s) + 2 SO2(g)

Calculate the amount of excess reactant left after 11.3 mol ZnS and 18.3 mol O₂react according to the following reaction:
2 ZnS_(s) + 3 O_2(g) → 2 ZnO_(s) + 2 SO_2(g)