consider-the-following-equilibrium-kc-2-68x10-3-at-800-c-caco3-s-cao-s-co2-g-is-

Question

Consider the following equilibrium (K_{c} = 2.68 × $$10^{−3} at 800$$ °C):CaCO_{3} (s) ⇌ CaO (s) + CO_{2} (g)Is the formation of products favored at equilibrium? What is/are the relative concentration/s of the species involved at equilibrium?

Accepted Answer

No, the formation of reactant is favored at equilibrium.[CO_{2}] = 2.68×$$10^{−3}$$

Answer

Yes, the formation of products is favored at equilibrium.[CO_{2}] = 2.68×$$10^{−3}$$

Answer

Yes, the formation of products is favored at equilibrium.[CaCO_{3}] = [CaO][CO_{2}]/2.68×$$10^{−3}$$[CaO] = 2.68×$$10^{−3}$$[CaCO_{3}]/[CO_{2}][CO_{2}] = 2.68×$$10^{−3}$$[CaCO_{3}]/[CaO]

Answer

No, the formation of reactant is favored at equilibrium.[CaCO_{3}] = [CaO][CO_{2}]/2.68×$$10^{−3}$$[CaO] = 2.68×$$10^{−3}$$[CaCO_{3}]/[CO_{2}][CO_{2}] = 2.68×$$10^{−3}$$[CaCO_{3}]/[CaO]

Consider the following equilibrium (Kc = 2.68 × 10−3 at 800 °C):CaCO3 (s) ⇌ CaO (s) + CO2 (g)Is the formation of products favored at equilibrium? What is/are the relative concentration/s of the species involved at equilibrium?

Consider the following equilibrium (K_c = 2.68 × 10⁻³ at 800 °C):
CaCO₃ (s) ⇌ CaO (s) + CO₂ (g)
Is the formation of products favored at equilibrium? What is/are the relative concentration/s of the species involved at equilibrium?