compare-the-hvap-values-for-water-isopropyl-alcohol-ether-and-ammonia-and-order-

Question

Arrange acetone ($$C_{3}$H_{6}O$$), water ($$H_{2}O$$), methylamine ($$CH_{3}NH$$_{2}), and propane ($$C_{3}H$$_{8}) in order of increasing ΔH_{vap} values. Explain the order using intermolecular forces of attraction.

Accepted Answer

Increasing ΔH_{vap} values: propane \u003c acetone \u003c methylamine \u003c water; The stronger the intermolecular forces of attraction the molecule exhibits, the larger its ΔH_{vap} value will be.

Answer

Increasing ΔH_{vap} values:  water \u003c methylamine \u003c acetone \u003c propane; The stronger the intermolecular forces of attraction the molecule exhibits, the larger its ΔH_{vap} value will be.

Answer

Increasing ΔH_{vap} values: propane \u003c acetone \u003c methylamine \u003c water; The weaker the intermolecular forces of attraction the molecule exhibits, the larger its ΔH_{vap} value will be.

Answer

Increasing ΔH_{vap} values:  water \u003c methylamine \u003c acetone \u003c propane; The weaker the intermolecular forces of attraction the molecule exhibits, the larger its ΔH_{vap} value will be.

Arrange acetone (C3H6O), water (H2O), methylamine (CH3NH2), and propane (C3H8) in order of increasing ΔHvap values. Explain the order using intermolecular forces of attraction.

Arrange acetone (C₃H₆O), water (H₂O), methylamine (CH₃NH₂), and propane (C₃H₈) in order of increasing ΔH_vap values. Explain the order using intermolecular forces of attraction.