write-chemical-equations-showing-how-each-substance-yields-ions-in-water-h2c2o4-

Question

Write chemical equations showing how each substance yields ions in water: $$H_{2}$C_{2}O$$_{4}, HBrO, Sr(OH)_{2}, and RbOH.

Accepted Answer

$$H_{2}$C_{2}O$$_{4} ⇌ 2 $$H^{+}$$ + $$C_{2}O$$_{4}^{2−}  HBrO ⇌ $$H^{+}$$ + $$BrO^{−}  Sr(OH$$)_{2} → $$Sr^{2+} + 2$$ $$OH^{−}$$  RbOH → $$Rb^{+}$$ + $$OH^{−}$$

Answer

$$H_{2}$C_{2}O$$_{4} ⇌ 2 $$OH^{−}$$ + $$C_{2}O$$_{2}^{2+}  HBrO ⇌ $$OH^{−}$$ + $$Br^{+}  Sr(OH$$)_{2} → 2 $$H^{+} + $$SrO_{2}^{2−}  RbOH → $$H^{+}$$ + $$RbO^{−}$$

Answer

$$H_{2}$C_{2}O$$_{4} ⇌  $$H^{2+}$$ + $$C_{2}O$$_{4}^{2−}  HBrO ⇌ $$H^{+}$$ + $$BrO^{−}  Sr(OH$$)_{2} → $$Sr^{2+}$$ + $$OH^{2−}$$  RbOH → $$Rb^{+}$$ + $$OH^{−}$$

Answer

$$H_{2}$C_{2}O$$_{4} ⇌ $$OH^{2−}$$ + $$C_{2}O$$_{2}^{2+}  HBrO ⇌ $$OH^{−}$$ + $$Br^{+}  Sr(OH$$)_{2} → $$H^{2+} + $$SrO_{2}^{2−}  RbOH → $$H^{+}$$ + $$RbO^{−}$$

Write chemical equations showing how each substance yields ions in water: H2C2O4, HBrO, Sr(OH)2, and RbOH.

Write chemical equations showing how each substance yields ions in water: H₂C₂O₄, HBrO, Sr(OH)₂, and RbOH.