-on-integers-by-f29-f03-f27-f51-create-f-1-explicitly-and-use-it-to-compute-f-17

Question

A one-to-one function f f is defined on integers by f(−2)=9f(−2)=9, f(0)=3f(0)=3, f(2)=7f(2)=7, f(5)=1f(5)=1. Create f−$$1f^{-1}$$ explicitly and use it to compute f−$$1(7)f^{-1}(7).$$

Accepted Answer

f−1={(9,−2),(3,0),(7,2),(1,5)}$$f^{-1}$$={\left\lbrace(9,-2),(3,0),(7,2),(1,5)\right\rbrace} f−1(7)=$$2f^{-1}(7) = 2 $$

Answer

f−$$1f^{-1}$$ does not exist because the outputs are not consecutive integersf−$$1(7)f^{-1}(7) is $$undefined

Answer

f−1={(9,2),(3,0),(7,−2),(1,5)}$$f^{-1}$$={\left\lbrace(9,2),(3,0),(7,-2),(1,5)\right\rbrace} f−1(7)=−$$2f^{-1}(7$$) = −2

Answer

f−1={(−2,9),(0,3),(2,7),(5,1)}$$f^{-1}$$={\left\lbrace(-2,9),(0,3),(2,7),(5,1)\right\rbrace} f−1(7)=$$5f^{-1}(7) = 5 $$

A one-to-one function f f is defined on integers by f(−2)=9f(−2)=9, f(0)=3f(0)=3, f(2)=7f(2)=7, f(5)=1f(5)=1. Create f−1f^{-1} explicitly and use it to compute f−1(7)f^{-1}(7).

A one-to-one function $f$ is defined on integers by $f (- 2) = 9$ , $f of 0 equals 3$ , $f of 2 equals 7$ , $f of 5 equals 1$ . Create $f^{- 1}$ explicitly and use it to compute $f inverse of 7$ .