0i1-log10i2-log10i3-condense-this-expression-into-a-single-log-of-the-form-log10

Question

A sound engineer combines two sound intensity ratios using decibels, which are proportional to logarithms: 0.5log⁡10(I1)+log⁡10(I2)−log⁡10(I3)0.5\log_{10}($$I_1$$)+\log_{10}($$I_2$$)-\log_{10}($$I_3). $$Condense this expression into a single logarithm.

Accepted Answer

log⁡10I1I2I3\log_{10}\frac{\sqrt{$$I_1$$}$$I_2$$}{$$I_3$$}

Answer

log⁡10(I10.5+I2−I3)\log_{10}($$I_1$$^{0.5} + $$I_2$$ - $$I_3) $$

Answer

0.5log⁡10(I1I2I3)0.5\log_{10}\left(\frac{I_1I_2}{$$I_3$$}\right)

Answer

log⁡10I1I2I3\log_{10}\sqrt{\frac{I_1I_2}{$$I_3$$}}

A sound engineer combines two sound intensity ratios using decibels, which are proportional to logarithms: 0.5log10(I1)+log10(I2)−log10(I3)0.5\(\log\)_{10}(I_1)+\(\log\)_{10}(I_2)-\(\log\)_{10}(I_3). Condense this expression into a single logarithm.

A sound engineer combines two sound intensity ratios using decibels, which are proportional to logarithms: $0.5 \log_{10} (I_{1}) + \log_{10} (I_{2}) - \log_{10} (I_{3})$ . Condense this expression into a single logarithm.