a-compound-malic-acid-has-a-specific-rotation-148-calculate-its-observed-rotatio

Question

An unknown compound's (+)-isomer has a specific rotation of $$+148^{o}. $$Calculate its observed rotation if a mixture contains 60.0 % (-)-isomer and 40.0 % (+)-isomer.

Accepted Answer

Observed rotation = -29.6

Answer

Observed rotation = -148

Answer

Observed rotation = +0.20

Answer

Observed rotation = +0.60

An unknown compound's (+)-isomer has a specific rotation of +148o. Calculate its observed rotation if a mixture contains 60.0 % (-)-isomer and 40.0 % (+)-isomer.

An unknown compound's (+)-isomer has a specific rotation of +148^o. Calculate its observed rotation if a mixture contains 60.0 % (-)-isomer and 40.0 % (+)-isomer.