Molecule I is expected to have a higher solubility in water than molecule II. Explain why.

Molecule I has fewer hydrogens than molecule II, making molecule I more polar than molecule II.

Molecule I is resonance stabilized and will have a higher dipole moment than molecule II.

Molecule I is more polar because it has more double bonds than molecule II.

Molecule I can exhibit resonance and form more hydrogen bonding with water than Molecule II.