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24. Electric Force & Field; Gauss' Law - Parte 3 di 3!
24. Electric Force & Field; Gauss' Law / Electric Flux with Calculus / Problema 9
Problema 9

A rectangular inspection window lies in the xyxy-plane spanning x=0x = 0 to LL and y=0y = 0 to WW, with length L=4.0L=4.0 m along xx and width W=1.5W=1.5 m along yy. The electric field is E⃗=(30xL)z^\(\vec{E}\)=\(\left\)(\(\frac{30x}{L}\)\(\right\))\(\hat{z}\) N/C, and the surface normal is +z^+\(\hat{z}\). Determine the electric flux through the window.