the-equation-z-t-c-dt2-gives-the-angular-velocity-of-a-rotating-particle-where-c

Question

The equation ω_{z}(t) = C - $$Dt^{2}$$ gives the angular velocity of a rotating particle, where C = 4.20 rad/s and D = 0.250 $$rad/s^{3}. $$Express its angular accleration in the form α(t) = ?

Accepted Answer

$$-(0.500rad/s^{3})t$$

Answer

$$4.20rad/s^{2}$$ - $$(0.250rad/s^{3})t$$

Answer

$$4.20rad/s^{2}$$ - $$(0.500rad/s^{3})t$$

Answer

$$-(0.250rad/s^{3})t$$

The equation ωz(t) = C - Dt2 gives the angular velocity of a rotating particle, where C = 4.20 rad/s and D = 0.250 rad/s3. Express its angular accleration in the form α(t) = ?

The equation ω_z(t) = C - Dt² gives the angular velocity of a rotating particle, where C = 4.20 rad/s and D = 0.250 rad/s³. Express its angular accleration in the form α(t) = ?