given-two-wave-functions-y1xt-2sinx-3t-and-y2xt-3cosx-3t-what-is-the-resultant-w

Question

Given two wave functions, y1(x,t) = 2sin(x - 3t) and y2(x,t) = 3cos(x - 3t), what is the resultant wave function y(x,t) using the principle of superposition?

Accepted Answer

y(x,t) = 2sin(x - 3t) + 3cos(x - 3t)

Answer

y(x,t) = 5sin(x - 3t)

Answer

y(x,t) = sin(x - 3t) + cos(x - 3t)

Answer

y(x,t) = 5cos(x - 3t)