33. Geometric Optics
Mirror Equation
33. Geometric Optics
Mirror Equation
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A 4 cm tall object is placed in 15 cm front of a concave mirror with a focal length of 5 cm. Where is the image produced? Is this image real or virtual? Is it upright or inverted? What is the height of the image?
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You want to produce a mirror that can produce an upright image that would be twice as tall as the object when placed 5 cm in front of it. What shape should this mirror be? What radius of curvature should the mirror have?
2253views2rank4comments - Scelta multiplaAn object is in front of a converging lens with a focal length of . Use ray tracing to determine the location of the image. Is the image upright or inverted?1891views
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A 4 cm tall object is placed 15 cm in front of a concave mirror with a focal length of 5 cm. Where is the image produced? Is this image real or virtual? Is it upright or inverted? What is the height of the image?
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