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Ch 15: Oscillations
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Non è quello che usi tu?Cambia libro di testo
Capitolo 15, Problema 16e

A 200 g mass attached to a horizontal spring oscillates at a frequency of 2.0 Hz. At t = 0 s, the mass is at x = 5.0 cm and has vx = -30 cm/s. Determine: The maximum speed.

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Convert the given values into SI units: mass (m) = 200 g = 0.2 kg, frequency (f) = 2.0 Hz, initial position (x₀) = 5.0 cm = 0.05 m, and initial velocity (vₓ₀) = -30 cm/s = -0.3 m/s.
Recall the relationship between angular frequency (ω) and frequency (f): ω = 2πf. Substitute f = 2.0 Hz into the formula to calculate ω.
The maximum speed (vₘₐₓ) in simple harmonic motion is given by the formula vₘₐₓ = Aω, where A is the amplitude of oscillation. To find A, use the equation for total energy in simple harmonic motion: E = (1/2)mω²A² = (1/2)m(vₓ₀² + ω²x₀²). Solve for A using the given initial conditions.
Once A is determined, substitute its value and the calculated ω into the formula vₘₐₓ = Aω to find the maximum speed.
Ensure all units are consistent and verify the calculations conceptually by checking that the maximum speed occurs when the mass passes through the equilibrium position (x = 0).

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