Domanda del libro di testo
Two positive point charges are 5.0 cm apart. If the electric potential energy is 72 μJ, what is the magnitude of the force between the two charges?
2165
views
Ch 25: The Electric Potential
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796
Non è quello che usi tu?Cambia libro di testoScegli un libro di testo diverso
TOC.tableOfContents
- Ch 01: Concepts of Motion35
- Ch 02: Kinematics in One Dimension75
- Ch 03: Vectors and Coordinate Systems58
- Ch 04: Kinematics in Two Dimensions60
- Ch 05: Force and Motion23
- Ch 06: Dynamics I: Motion Along a Line53
- Ch 07: Newton's Third Law27
- Ch 08: Dynamics II: Motion in a Plane52
- Ch 09: Work and Kinetic Energy56
- Ch 10: Interactions and Potential Energy50
- Ch 11: Impulse and Momentum56
- Ch 12: Rotation of a Rigid Body71
- Ch 13: Newton's Theory of Gravity52
- Ch 14: Fluids and Elasticity44
- Ch 15: Oscillations55
- Ch 16: Traveling Waves37
- Ch 17: Superposition39
- Ch 18: A Macroscopic Description of Matter53
- Ch 19: Work, Heat, and the First Law of Thermodynamics60
- Ch 20: The Micro/Macro Connection53
- Ch 21: Heat Engines and Refrigerators34
- Ch 22: Electric Charges and Forces40
- Ch 23: The Electric Field39
- Ch 24: Gauss' Law32
- Ch 25: The Electric Potential63
- Ch 26: Potential and Field57
- Ch 27: Current and Resistance42
- Ch 28: Fundamentals of Circuits39
- Ch 29: The Magnetic Field47
- Ch 30: Electromagnetic Induction60
- Ch 31: Electromagnetic Fields and Waves32
- Ch 32: AC Circuits63
- Ch 33: Wave Optics32
- Ch 34: Ray Optics57
- Ch 35: Optical Instruments30
- Ch 36: Special Relativity38
- Ch 37: The Foundations of Modern Physics25
- Ch 38: Quantization49
- Ch 39: Wave Functions and Uncertainty31
- Ch 40: One-Dimensional Quantum Mechanics35
- Ch 41: Atomic Physics18
- Ch 42: Nuclear Physics27
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Non è quello che usi tu?Cambia libro di testo
Capitolo 25, Problema 1
The electric field strength is 50,000 N/C inside a parallel-plate capacitor with a 2.0 mm spacing. A proton is released from rest at the positive plate. What is the proton's speed when it reaches the negative plate?
Guida verificata passo dopo passo1
Identify the key variables: The electric field strength \( E = 50,000 \, \text{N/C} \), the distance between the plates \( d = 2.0 \times 10^{-3} \; \text{m} \), and the charge and mass of the proton \( q = 1.6 \times 10^{-19} \; \text{C} \) and \( m = 1.67 \times 10^{-27} \; \text{kg} \), respectively.
Calculate the potential difference \( V \) between the plates using the relationship \( V = E \cdot d \). Substitute the given values for \( E \) and \( d \) to find \( V \).
Determine the kinetic energy of the proton when it reaches the negative plate. The work done on the proton by the electric field is equal to the change in its kinetic energy. Use the formula \( W = q \cdot V \), where \( W \) is the work done, \( q \) is the charge of the proton, and \( V \) is the potential difference.
Relate the work done to the proton's kinetic energy using \( W = \frac{1}{2} m v^2 \), where \( m \) is the mass of the proton and \( v \) is its final speed. Solve for \( v \) by rearranging the equation: \( v = \sqrt{\frac{2 W}{m}} \).
Substitute the expression for \( W \) (from step 3) into the equation for \( v \) and calculate \( v \) using the known values of \( q \), \( V \), and \( m \). This will give the proton's speed when it reaches the negative plate.
Risposta video verificata per un problema simile:
Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Concetti chiave
Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.
Electric Field
An electric field is a region around a charged object where other charged objects experience a force. The strength of the electric field (E) is defined as the force (F) per unit charge (q), measured in newtons per coulomb (N/C). In this scenario, the electric field strength of 50,000 N/C indicates the force acting on a proton as it moves between the plates of the capacitor.
Video consigliato:
Percorso guidato
03:16
Intro to Electric Fields
Kinematics of Charged Particles
When a charged particle, such as a proton, moves in an electric field, it experiences acceleration due to the force exerted by the field. The kinematic equations can be used to determine the final speed of the particle as it travels a certain distance. In this case, the distance between the plates and the initial conditions (starting from rest) are crucial for calculating the proton's final speed.
Video consigliato:
Percorso guidato
08:25Kinematics Equations
Energy Conservation
The principle of energy conservation states that energy cannot be created or destroyed, only transformed from one form to another. In the context of the capacitor, the electric potential energy of the proton is converted into kinetic energy as it accelerates towards the negative plate. This relationship can be expressed mathematically, allowing for the calculation of the proton's speed based on the electric field and distance traveled.
Video consigliato:
Percorso guidato
06:24Conservation Of Mechanical Energy
Pratica correlata
Domanda del libro di testo
What is the electric potential energy of the group of charges in FIGURE EX25.5?
526
views
Domanda del libro di testo
An electron is released from rest at the center of a parallel-plate capacitor that has a 1.0 mm spacing. The electron then strikes one of the plates with a speed of 1.5×106 m/s. What is the electric field strength inside the capacitor?
3045
views