Ch 30: Electromagnetic Induction

Knight Calc - Physics for Scientists and Engineers 5th Edition

Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Non è quello che usi tu?Cambia libro di testo

Knight Calc 5th Edition

Ch 30: Electromagnetic Induction

Problema 43b

Capitolo 30, Problema 43b

CALC An 8.0 cm×8.0 cm square loop is halfway into a magnetic field perpendicular to the plane of the loop. The loop's mass is 10 g and its resistance is 0.010 Ω. A switch is closed at t = 0 s, causing the magnetic field to increase from 0 to 1.0 T in 0.010 s. Hint: What is the impulse on the loop? With what speed is the loop 'kicked' away from the magnetic field?

Guida verificata passo dopo passo

Step 1: Calculate the area of the square loop. The loop is 8.0 cm × 8.0 cm, so the area can be calculated using the formula $ A = l \times w $, where $ l $ and $ w $ are the length and width of the loop. Convert the dimensions to meters before calculating.

Step 2: Determine the change in magnetic flux through the loop. Magnetic flux $ \Phi $ is given by $ \Phi = B \times A $, where $ B $ is the magnetic field strength and $ A $ is the area of the loop. Since the magnetic field changes from 0 to 1.0 T, calculate the change in flux $ \Delta \Phi $.

Step 3: Calculate the induced electromotive force (EMF) in the loop using Faraday's law of induction. Faraday's law states $ \text{EMF} = - \frac{\Delta \Phi}{\Delta t} $, where $ \Delta t $ is the time interval over which the magnetic field changes. Substitute the values for $ \Delta \Phi $ and $ \Delta t $.

Step 4: Determine the induced current in the loop using Ohm's law. Ohm's law states $ I = \frac{\text{EMF}}{R} $, where $ R $ is the resistance of the loop. Substitute the calculated EMF and the given resistance to find the current.

Step 5: Calculate the impulse on the loop. The force on the loop is due to the interaction between the induced current and the magnetic field. The impulse $ J $ can be calculated using $ J = F \times \Delta t $, where $ F $ is the magnetic force given by $ F = I \times L \times B $, with $ L $ being the length of the side of the loop. Use the impulse-momentum theorem $ J = m \times v $ to find the speed $ v $ of the loop, where $ m $ is the mass of the loop.

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Faraday's Law of Electromagnetic Induction

Faraday's Law states that a change in magnetic flux through a loop induces an electromotive force (EMF) in the loop. The induced EMF is proportional to the rate of change of the magnetic flux, which can be calculated using the formula EMF = -dΦ/dt, where Φ is the magnetic flux. This principle is crucial for understanding how the changing magnetic field in the problem generates an induced current in the loop.

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Percorso guidato

09:26

Faraday's Law

Lorentz Force

The Lorentz force describes the force experienced by a charged particle moving through a magnetic field. It is given by the equation F = q(v × B), where F is the force, q is the charge, v is the velocity of the particle, and B is the magnetic field. In the context of the loop, the induced current creates a magnetic field that interacts with the external magnetic field, resulting in a net force that 'kicks' the loop away.

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Percorso guidato

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Lorentz Transformations of Velocity

Impulse and Momentum

Impulse is defined as the change in momentum of an object when a force is applied over a period of time. It can be calculated using the formula Impulse = FΔt, where F is the force and Δt is the time duration. In this scenario, the impulse on the loop can be determined from the Lorentz force acting on it, leading to a change in its momentum and ultimately giving it a speed as it moves away from the magnetic field.

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Impulse & Impulse-Momentum Theorem

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