A 1.0-cm-tall object is 10 cm in front of a converging lens that has a 30 cm focal length. Calculate the image position and height. Compare with your ray-tracing answers in part a.
Ch 34: Ray Optics
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Non è quello che usi tu?Cambia libro di testo
Capitolo 34, Problema 31
A 1.0-cm-tall candle flame is 60 cm from a lens with a focal length of 20 cm. What are the distance and the height of the flame's image?
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Identify the given values: The object height \( h_o \) is 1.0 cm, the object distance \( d_o \) is 60 cm, and the focal length \( f \) is 20 cm. We need to find the image distance \( d_i \) and the image height \( h_i \).
Use the lens formula to find the image distance \( d_i \): \( \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \). Rearrange this equation to solve for \( \frac{1}{d_i} \): \( \frac{1}{d_i} = \frac{1}{f} - \frac{1}{d_o} \). Substitute the given values for \( f \) and \( d_o \).
After calculating \( \frac{1}{d_i} \), take the reciprocal to find \( d_i \), the image distance. This will tell you where the image is located relative to the lens.
To find the image height \( h_i \), use the magnification formula: \( M = \frac{h_i}{h_o} = -\frac{d_i}{d_o} \). Rearrange this to solve for \( h_i \): \( h_i = M \cdot h_o \). Substitute the values for \( M \), \( h_o \), and \( d_i \).
Interpret the results: The sign of \( d_i \) will indicate whether the image is real or virtual (positive for real, negative for virtual), and the sign of \( h_i \) will indicate whether the image is upright or inverted (positive for upright, negative for inverted).

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Concetti chiave
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Lens Formula
The lens formula relates the object distance (u), image distance (v), and focal length (f) of a lens. It is expressed as 1/f = 1/v - 1/u. This formula is essential for determining the position of the image formed by the lens based on the position of the object.
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Lens Maker Equation
Magnification
Magnification is the ratio of the height of the image (h') to the height of the object (h), and it can also be expressed as the negative ratio of the image distance (v) to the object distance (u). It is given by the formula M = h'/h = -v/u. Understanding magnification helps in determining how the size of the image compares to the size of the object.
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Mirror Equation
Sign Convention in Optics
In optics, the sign convention dictates how distances are measured in relation to the lens. Typically, distances measured in the direction of the incoming light are considered negative, while those in the direction of outgoing light are positive. This convention is crucial for correctly applying the lens formula and calculating image properties.
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Net Torque & Sign of Torque
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