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Ch 38: Quantization
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Non è quello che usi tu?Cambia libro di testo
Capitolo 38, Problema 52

An electron confined in a one-dimensional box emits a 200 nm photon in a quantum jump from n = 2 to n = 1. What is the length of the box?

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Step 1: Understand the problem. The electron is confined in a one-dimensional box, which means its energy levels are quantized according to the particle-in-a-box model. The problem involves a quantum jump from n=2 to n=1, emitting a photon of wavelength 200 nm. We need to find the length of the box.
Step 2: Recall the energy levels for a particle in a one-dimensional box. The energy of the nth level is given by the formula: En=n2h28mL2, where n is the quantum number, h is Planck's constant, m is the mass of the electron, and L is the length of the box.
Step 3: Calculate the energy difference between the two levels (ΔE). The energy difference is given by: ΔE=E2-E1. Substitute the formula for energy levels into this expression: ΔE=22h28mL2-12h28mL2.
Step 4: Relate the energy difference to the emitted photon. The energy of the photon is given by: E=hcλ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon (200 nm). Set this equal to ΔE: hcλ=ΔE. Substitute the expression for ΔE from Step 3.
Step 5: Solve for the length of the box (L). Rearrange the equation to isolate L: L=8mhcλh2(22-12). Substitute the known values for h, c, m (mass of the electron), and λ (200 nm) to calculate L.

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Quantum mechanics is the branch of physics that deals with the behavior of particles at the atomic and subatomic levels. It introduces concepts such as quantization, where certain properties, like energy, can only take on discrete values. This framework is essential for understanding phenomena like electron transitions in atoms and the emission of photons.
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