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Ch 10: Dynamics of Rotational Motion
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Non è quello che usi tu?Cambia libro di testo
Capitolo 10, Problema 16b

A 12.0-kg box resting on a horizontal, frictionless surface is attached to a 5.00-kg weight by a thin, light wire that passes over a frictionless pulley (Fig. E10.16). The pulley has the shape of a uniform solid disk of mass 2.00 kg and diameter 0.500 m. After the system is released, find the acceleration of the box.

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Identify the forces acting on the system: The 5.00-kg weight experiences a gravitational force downward, which is the driving force for the system. The tension in the wire acts upward on the 5.00-kg weight and horizontally on the 12.0-kg box.
Apply Newton's second law to the 5.00-kg weight: The net force on the weight is the difference between the gravitational force and the tension in the wire. This can be expressed as: \( m_2 g - T = m_2 a \), where \( m_2 = 5.00 \text{ kg} \), \( g = 9.81 \text{ m/s}^2 \), and \( a \) is the acceleration.
Apply Newton's second law to the 12.0-kg box: The only horizontal force on the box is the tension in the wire, so \( T = m_1 a \), where \( m_1 = 12.0 \text{ kg} \).
Consider the rotational motion of the pulley: The torque on the pulley due to the tension is \( \tau = T R \), where \( R = 0.250 \text{ m} \) is the radius of the pulley. The moment of inertia of the pulley is \( I = \frac{1}{2} m R^2 \), where \( m = 2.00 \text{ kg} \). The angular acceleration \( \alpha \) is related to the linear acceleration by \( \alpha = \frac{a}{R} \).
Combine the equations: Use the relationship between torque and angular acceleration \( \tau = I \alpha \) to find \( T \) in terms of \( a \). Substitute this expression into the equations for the 5.00-kg weight and the 12.0-kg box to solve for the acceleration \( a \).

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Newton's Second Law

Newton's Second Law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass (F = ma). In this problem, it helps determine the acceleration of the box by considering the forces acting on both the box and the weight, including gravitational force and tension in the wire.
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Rotational Dynamics

Rotational dynamics involves the study of objects in rotational motion, where torque and angular acceleration play key roles. The pulley in this problem is a solid disk, and its rotational inertia affects the system's dynamics. Understanding how the torque due to the tension in the wire causes angular acceleration in the pulley is crucial for solving the problem.
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Conservation of Energy

Conservation of energy states that energy in a closed system remains constant. In this scenario, the potential energy of the weight is converted into kinetic energy of the box and rotational kinetic energy of the pulley. Analyzing energy transformations helps in understanding the system's behavior and calculating the acceleration of the box.
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