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Ch 25: Current, Resistance, and EMF
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Non è quello che usi tu?Cambia libro di testo
Capitolo 25, Problema 42

The battery for a certain cell phone is rated at 3.70 V. According to the manufacturer, it can produce 3.15 × 104 J of electrical energy, enough for 5.25 h of operation, before needing to be recharged. Find the average current that this cell phone draws when turned on.

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First, understand that the power consumed by the cell phone can be calculated using the formula for power: \( P = \frac{E}{t} \), where \( E \) is the energy in joules and \( t \) is the time in seconds.
Convert the time from hours to seconds. Since there are 3600 seconds in an hour, multiply 5.25 hours by 3600 to get the time in seconds.
Substitute the given energy \( E = 3.15 \times 10^4 \) J and the converted time \( t \) into the power formula to find the power \( P \).
Use the relationship between power, voltage, and current: \( P = IV \), where \( I \) is the current and \( V \) is the voltage. Rearrange this formula to solve for the current: \( I = \frac{P}{V} \).
Substitute the calculated power \( P \) and the given voltage \( V = 3.70 \) V into the formula to find the average current \( I \).

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Voltage

Voltage, measured in volts (V), is the electric potential difference between two points. It represents the energy per unit charge available to drive electric current through a circuit. In this problem, the cell phone battery is rated at 3.70 V, indicating the potential energy available to power the device.
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Percorso guidato
07:14
RMS Current and Voltage

Energy

Energy, measured in joules (J), is the capacity to do work or produce change. Electrical energy is the energy carried by moving electrons in an electric circuit. The battery can produce 3.15 * 10^4 J, which is the total energy available for the phone's operation over a specified period.
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Percorso guidato
04:10
Intro to Energy & Types of Energy

Current

Current, measured in amperes (A), is the rate at which electric charge flows through a conductor. It is calculated by dividing the total energy by the product of voltage and time. In this problem, finding the average current involves using the given energy, voltage, and operational time to determine how much charge flows per second.
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Percorso guidato
05:38
Intro to Current
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