Skip to main content
Ch 26: Direct-Current Circuits
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Non è quello che usi tu?Cambia libro di testo
Capitolo 26, Problema 10a

Power Rating of a Resistor. The power rating of a resistor is the maximum power the resistor can safely dissipate without too great a rise in temperature and hence damage to the resistor. If the power rating of a 15 kΩ resistor is 5.0 W, what is the maximum allowable potential difference across the terminals of the resistor?

Guida verificata passo dopo passo
1
Understand the relationship between power, voltage, and resistance. The formula for power dissipated by a resistor is given by: P=V2R, where P is the power, V is the voltage, and R is the resistance.
Identify the given values: The power rating P is 5.0 W and the resistance R is 15 kΩ (which is 15,000 Ω).
Rearrange the formula to solve for the voltage V: V=P×R.
Substitute the known values into the rearranged formula: V=5.0×15000.
Calculate the square root to find the maximum allowable potential difference V across the terminals of the resistor.

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
2m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Power Rating

The power rating of a resistor indicates the maximum power it can dissipate safely without overheating. It is crucial for preventing damage due to excessive heat, which can alter the resistor's properties or cause it to fail. The power rating is typically specified in watts (W) and helps in selecting the appropriate resistor for a given application.
Video consigliato:

Ohm's Law

Ohm's Law is a fundamental principle in electronics that relates voltage (V), current (I), and resistance (R) in a circuit: V = I * R. This law is essential for calculating the potential difference across a resistor when the current and resistance are known, or vice versa. It provides a basis for understanding how electrical components interact in a circuit.
Video consigliato:
Percorso guidato
03:07
Resistance and Ohm's Law

Power Dissipation in Resistors

Power dissipation in resistors is calculated using the formula P = V^2 / R, where P is the power, V is the voltage across the resistor, and R is the resistance. This concept is vital for determining how much power a resistor can handle without exceeding its power rating, ensuring safe operation within electrical circuits.
Video consigliato:
Percorso guidato
06:18
Power in Circuits
Pratica correlata
Domanda del libro di testo

Power Rating of a Resistor. The power rating of a resistor is the maximum power the resistor can safely dissipate without too great a rise in temperature and hence damage to the resistor. A 100.0 Ω and a 150.0 Ω resistor, both rated at 2.00 W, are connected in series across a variable potential difference. What is the greatest this potential difference can be without overheating either resistor, and what is the rate of heat generated in each resistor under these conditions?

3130
views
Domanda del libro di testo

A triangular array of resistors is shown in Fig. E26.5. What current will this array draw from a 35.0 V battery having negligible internal resistance if we connect it across ac?

1468
views
Domanda del libro di testo

A triangular array of resistors is shown in Fig. E26.5. What current will this array draw from a 35.0 V battery having negligible internal resistance if we connect it across bc?

1597
views
1
rank
Domanda del libro di testo

Power Rating of a Resistor. The power rating of a resistor is the maximum power the resistor can safely dissipate without too great a rise in temperature and hence damage to the resistor. A 9.0 kΩ resistor is to be connected across a 120 V potential difference. What power rating is required?

1659
views
Domanda del libro di testo

A triangular array of resistors is shown in Fig. E26.5. If the battery has an internal resistance of 3.00Ω, what current will the array draw if the battery is connected across bc?

1865
views
Domanda del libro di testo

Light Bulbs in Series and in Parallel. Two light bulbs have constant resistances of 400Ω and 800Ω. If the two light bulbs are connected in series across a 120-V line, find the current through each bulb.

1936
views
1
rank