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Ch 33: The Nature and Propagation of Light
Young & Freedman Calc - University Physics 15th Edition
Young & Freedman Calc15th EditionUniversity PhysicsISBN: 9780135159552Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoYoung & Freedman Calc 15th EditionCh 33: The Nature and Propagation of LightProblema 35a
Capitolo 32, Problema 35a

A beam of white light passes through a uniform thickness of air. If the intensity of the scattered light in the middle of the green part of the visible spectrum is I, find the intensity (in terms of I) of scattered light in the middle of the red part of the spectrum.

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1
Understand the concept of Rayleigh scattering, which explains how light is scattered by particles much smaller than the wavelength of light. The intensity of scattered light is inversely proportional to the fourth power of the wavelength: \( I \propto \frac{1}{\lambda^4} \).
Identify the wavelengths for the green and red parts of the visible spectrum. Green light typically has a wavelength around 550 nm, while red light is around 650 nm.
Express the intensity of scattered light for green light as \( I_g \) and for red light as \( I_r \). Since \( I_g \propto \frac{1}{\lambda_g^4} \) and \( I_r \propto \frac{1}{\lambda_r^4} \), we can relate \( I_r \) to \( I_g \) using the ratio of their wavelengths.
Set up the equation for the intensity ratio: \( \frac{I_r}{I_g} = \left( \frac{\lambda_g}{\lambda_r} \right)^4 \). Substitute the known wavelengths for green and red light into this equation.
Solve the equation to express \( I_r \) in terms of \( I_g \). This will give you the intensity of scattered light in the middle of the red part of the spectrum in terms of the intensity \( I \) of the green part.

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Rayleigh Scattering

Rayleigh scattering is the scattering of light or other electromagnetic radiation by particles much smaller than the wavelength of the light. It is responsible for the blue color of the sky and explains why shorter wavelengths (like blue and green) scatter more than longer wavelengths (like red). The intensity of scattered light is inversely proportional to the fourth power of the wavelength.
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Law of Reflection

Visible Light Spectrum

The visible light spectrum is the portion of the electromagnetic spectrum that is visible to the human eye, ranging from approximately 380 nm to 750 nm. It includes colors from violet to red, with violet having the shortest wavelength and red the longest. Understanding the spectrum is crucial for analyzing how different wavelengths scatter differently.
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The Electromagnetic Spectrum

Intensity of Light

Intensity of light refers to the power per unit area carried by a wave. In the context of scattering, it is the amount of light energy scattered in a particular direction. The intensity of scattered light depends on factors like the wavelength of the light and the size of the scattering particles, as described by Rayleigh's law.
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Wave Intensity
Pratica correlata
Domanda del libro di testo

Unpolarized light with intensity I0 is incident on two polarizing filters. The axis of the first filter makes an angle of 60.0° with the vertical, and the axis of the second filter is horizontal. What is the intensity of the light after it has passed through the second filter?

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Domanda del libro di testo

Light of original intensity I0 passes through two ideal polarizing filters having their polarizing axes oriented as shown in Fig. E33.28. You want to adjust the angle f so that the intensity at point P is equal to I0/10. If the original light is linearly polarized in the same direction as the polarizing axis of the first polarizer the light reaches, what should Φ be?

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Domanda del libro di testo

Light of original intensity I0 passes through two ideal polarizing filters having their polarizing axes oriented as shown in Fig. E33.28. You want to adjust the angle f so that the intensity at point P is equal to I0/10. If the original light is unpolarized, what should Φ be?

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