Given the following vector, $v$, obtain the unit vector that aligns with the direction of $v$.
$v=-i-\sqrt{3}j$

$-\frac{1}{4}i+\frac{\sqrt{3}}{4}j$

$-\frac{1}{2}i-\frac{\sqrt{3}}{2}j$

$-\frac{1}{2}i+\frac{\sqrt{3}}{2}j$

$-\frac{1}{4}i-\frac{\sqrt{3}}{4}j$