Skip to main content
Ch. 1 - Angles and the Trigonometric Functions
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Non è quello che usi tu?Cambia libro di testo
Capitolo 1, Problema 29

In Exercises 25–30, use an identity to find the value of each expression. Do not use a calculator. sec² 23° - tan² 23°

Guida verificata passo dopo passo
1
Recall the Pythagorean identity involving secant and tangent: \(\sec^{2} \theta - \tan^{2} \theta = 1\).
Identify the angle in the problem: here, \(\theta = 23^\circ\).
Apply the identity directly by substituting \(\theta = 23^\circ\) into the expression: \(\sec^{2} 23^\circ - \tan^{2} 23^\circ\).
Since the identity holds for all angles where these functions are defined, the expression simplifies to 1 without further calculation.
Therefore, the value of \(\sec^{2} 23^\circ - \tan^{2} 23^\circ\) is 1 by the Pythagorean identity.

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
4m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Pythagorean Identity for Secant and Tangent

The identity sec²θ - tan²θ = 1 is a fundamental Pythagorean identity in trigonometry. It relates the secant and tangent functions of the same angle and allows simplification of expressions without a calculator.
Video consigliato:
Percorso guidato
6:25
Pythagorean Identities

Definition of Secant and Tangent Functions

Secant (sec θ) is the reciprocal of cosine (1/cos θ), and tangent (tan θ) is the ratio of sine to cosine (sin θ/cos θ). Understanding these definitions helps in applying identities and simplifying trigonometric expressions.
Video consigliato:
Percorso guidato
6:22
Graphs of Secant and Cosecant Functions

Using Identities to Simplify Expressions

Trigonometric identities allow rewriting complex expressions into simpler forms. Recognizing which identity applies enables solving problems efficiently without numerical approximation or calculators.
Video consigliato:
Percorso guidato
6:36
Simplifying Trig Expressions