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Ch. 1 - Angles and the Trigonometric Functions
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Non è quello che usi tu?Cambia libro di testo
Capitolo 1, Problema 1.2.63

In Exercises 63–68, find the exact value of each expression. Do not use a calculator. tan(𝜋/3)/2 - 1/sec(𝜋/6)

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Identify the given expression: \(\frac{\tan \frac{\pi}{3} - 1}{2 \sec \frac{\pi}{6}}\).
Recall the exact values of the trigonometric functions involved: \(\tan \frac{\pi}{3} = \sqrt{3}\), and \(\sec \frac{\pi}{6} = \frac{1}{\cos \frac{\pi}{6}}\).
Find \(\cos \frac{\pi}{6}\) using the known exact value: \(\cos \frac{\pi}{6} = \frac{\sqrt{3}}{2}\), so \(\sec \frac{\pi}{6} = \frac{1}{\frac{\sqrt{3}}{2}} = \frac{2}{\sqrt{3}}\).
Substitute these values back into the expression: \(\frac{\sqrt{3} - 1}{2 \times \frac{2}{\sqrt{3}}}\).
Simplify the denominator and then the entire fraction step-by-step, rationalizing denominators if necessary, to find the exact value.

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