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Ch. 3 - Trigonometric Identities and Equations
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.RE.38c

In Exercises 35–38, find the exact value of the following under the given conditions:
c. tan(α + β)
sin α = -1/3, 𝝅 < α < 3𝝅/2, and cos β = -1/3, 𝝅 < β < 3𝝅/2

Guida verificata passo dopo passo
1
Identify the given information: \( \sin \alpha = -\frac{1}{3} \) with \( \pi < \alpha < \frac{3\pi}{2} \), and \( \cos \beta = -\frac{1}{3} \) with \( \pi < \beta < \frac{3\pi}{2} \). Both angles are in the third quadrant.
Determine \( \cos \alpha \) using the Pythagorean identity: \( \sin^2 \alpha + \cos^2 \alpha = 1 \). Substitute \( \sin \alpha = -\frac{1}{3} \) and solve for \( \cos \alpha \). Since \( \alpha \) is in the third quadrant, \( \cos \alpha \) will be negative.
Determine \( \sin \beta \) using the Pythagorean identity: \( \sin^2 \beta + \cos^2 \beta = 1 \). Substitute \( \cos \beta = -\frac{1}{3} \) and solve for \( \sin \beta \). Since \( \beta \) is in the third quadrant, \( \sin \beta \) will be negative.
Calculate \( \tan \alpha = \frac{\sin \alpha}{\cos \alpha} \) and \( \tan \beta = \frac{\sin \beta}{\cos \beta} \) using the values found in previous steps.
Use the tangent addition formula to find \( \tan(\alpha + \beta) \): \[ \tan(\alpha + \beta) = \frac{\tan \alpha + \tan \beta}{1 - \tan \alpha \tan \beta} \] Substitute the values of \( \tan \alpha \) and \( \tan \beta \) to express \( \tan(\alpha + \beta) \) exactly.

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