Exercises 39–52 involve trigonometric equations quadratic in form. Solve each equation on the interval [0, 2𝝅). 4 cos² x - 1 = 0
Ch. 3 - Trigonometric Identities and Equations

Tutti i libri di testo
Blitzer 3rd Edition
Ch. 3 - Trigonometric Identities and Equations
Problema 3.3.42
Blitzer 3rd Edition
Ch. 3 - Trigonometric Identities and Equations
Problema 3.3.42Capitolo 3, Problema 3.3.42
In Exercises 39–46, use a half-angle formula to find the exact value of each expression. sin 105°
Guida verificata passo dopo passo1
Recognize that 105° can be expressed as twice an angle, which allows the use of the half-angle formula. Since 105° = 2 × 52.5°, we can set \( \theta = 52.5^\circ \).
Recall the half-angle formula for sine:
\[ \sin\left(\frac{\theta}{2}\right) = \pm \sqrt{\frac{1 - \cos(\theta)}{2}} \]
Since we want \( \sin(105^\circ) = \sin(2 \times 52.5^\circ) \), we can rewrite it as \( \sin(105^\circ) = 2 \sin(52.5^\circ) \cos(52.5^\circ) \), but to use the half-angle formula directly, consider \( 105^\circ = 210^\circ / 2 \).
Alternatively, express 105° as half of 210°, so \( \theta = 210^\circ \). Then apply the half-angle formula:
\[ \sin(105^\circ) = \sin\left(\frac{210^\circ}{2}\right) = \pm \sqrt{\frac{1 - \cos(210^\circ)}{2}} \]
Determine the sign of the sine value at 105°. Since 105° is in the second quadrant where sine is positive, choose the positive root.
Find \( \cos(210^\circ) \) using known values or the unit circle, then substitute into the half-angle formula:
\[ \sin(105^\circ) = + \sqrt{\frac{1 - \cos(210^\circ)}{2}} \]
This expression gives the exact value of \( \sin(105^\circ) \).

Risposta video verificata per un problema simile:
Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
5mConcetti chiave
Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.
Half-Angle Formulas
Half-angle formulas express the sine, cosine, or tangent of half an angle in terms of the cosine of the original angle. For sine, the formula is sin(θ/2) = ±√[(1 - cos θ)/2], where the sign depends on the quadrant of θ/2. These formulas help find exact trigonometric values for angles not commonly found on the unit circle.
Video consigliato:
Percorso guidato
Quadratic Formula
Angle Decomposition
To use half-angle formulas effectively, the given angle must be expressed as twice another angle whose trigonometric values are known. For example, 105° can be written as 210°/2, allowing the use of the half-angle formula with θ = 210°. This step is crucial for applying the formula correctly.
Video consigliato:
Percorso guidato
Coterminal Angles
Sign Determination Based on Quadrants
When applying half-angle formulas, determining the correct sign (positive or negative) of the result depends on the quadrant in which the half-angle lies. Since sin 105° is positive (second quadrant), the positive root is chosen. Understanding quadrant signs ensures the exact value reflects the correct trigonometric sign.
Video consigliato:
Percorso guidato
Quadratic Formula
Pratica correlata
Domanda del libro di testo
455
views
Domanda del libro di testo
In Exercises 43–44, express each product as a sum or difference. sin 7x cos 3x
701
views
Domanda del libro di testo
Exercises 39–52 involve trigonometric equations quadratic in form. Solve each equation on the interval [0, 2𝝅). 2 sin² x - sin x - 1 = 0
548
views
Domanda del libro di testo
In Exercises 47–54, use the figures to find the exact value of each trigonometric function. sin(θ/2)
784
views
Domanda del libro di testo
In Exercises 54–67, solve each equation on the interval [0, 2𝝅). Use exact values where possible or give approximate solutions correct to four decimal places. cos 2x = -1
527
views
Domanda del libro di testo
In Exercises 35–38, find the exact value of the following under the given conditions:
a. sin(α + β)
sin α = 3/5, 0 < α < 𝝅/2, and sin β = 12/13, 𝝅/2 < β < 𝝅.
783
views