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Ch. 3 - Trigonometric Identities and Equations
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.RE.35a

In Exercises 35–38, find the exact value of the following under the given conditions:
a. sin(α + β)
sin α = 3/5, 0 < α < 𝝅/2, and sin β = 12/13, 𝝅/2 < β < 𝝅.

Guida verificata passo dopo passo
1
Identify the given information: \( \sin \alpha = \frac{3}{5} \) with \( 0 < \alpha < \frac{\pi}{2} \), and \( \sin \beta = \frac{12}{13} \) with \( \frac{\pi}{2} < \beta < \pi \).
Determine the quadrants for \( \alpha \) and \( \beta \) to find the signs of \( \cos \alpha \) and \( \cos \beta \). Since \( \alpha \) is in the first quadrant, \( \cos \alpha > 0 \). Since \( \beta \) is in the second quadrant, \( \cos \beta < 0 \).
Use the Pythagorean identity to find \( \cos \alpha \) and \( \cos \beta \): \[ \cos \theta = \pm \sqrt{1 - \sin^2 \theta} \] Calculate: \[ \cos \alpha = +\sqrt{1 - \left(\frac{3}{5}\right)^2} \] \[ \cos \beta = -\sqrt{1 - \left(\frac{12}{13}\right)^2} \]
Apply the sine addition formula: \[ \sin(\alpha + \beta) = \sin \alpha \cos \beta + \cos \alpha \sin \beta \]
Substitute the known values of \( \sin \alpha \), \( \cos \alpha \), \( \sin \beta \), and \( \cos \beta \) into the formula to express \( \sin(\alpha + \beta) \) exactly.

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