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Ch. 2 - Acute Angles and Right Triangles
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 38

Find one solution for each equation. Assume all angles involved are acute angles. See Example 3. cos(2θ + 50°) = sin(2θ - 20°)

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Recall the co-function identity in trigonometry: \(\sin x = \cos(90^\circ - x)\). Use this to rewrite the right side of the equation \(\cos(2\theta + 50^\circ) = \sin(2\theta - 20^\circ)\) as \(\cos(90^\circ - (2\theta - 20^\circ))\).
Simplify the expression inside the cosine on the right side: \(90^\circ - (2\theta - 20^\circ) = 90^\circ - 2\theta + 20^\circ = 110^\circ - 2\theta\).
Now the equation becomes \(\cos(2\theta + 50^\circ) = \cos(110^\circ - 2\theta)\). Since the cosines of two angles are equal, set the angles equal to each other or their supplements: either \(2\theta + 50^\circ = 110^\circ - 2\theta\) or \(2\theta + 50^\circ = 360^\circ - (110^\circ - 2\theta)\).
Solve the first equation \(2\theta + 50^\circ = 110^\circ - 2\theta\) for \(\theta\) by isolating \(\theta\) on one side.
Check the solution to ensure \(\theta\) is an acute angle (between \(0^\circ\) and \(90^\circ\)). If it is, this is a valid solution. If not, solve the second equation and check again.

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