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Ch. 2 - Acute Angles and Right Triangles
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 81

Suppose θ is in the interval (90°, 180°). Find the sign of each of the following. sin(-θ)

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Recall the interval for \( \theta \) is \( (90^\circ, 180^\circ) \), which means \( \theta \) is in the second quadrant.
Understand that \( -\theta \) is the negative of an angle in the second quadrant, so \( -\theta \) lies in the interval \( (-180^\circ, -90^\circ) \), which corresponds to the third or fourth quadrant when considering standard position angles.
Use the odd function property of sine: \( \sin(-\theta) = -\sin(\theta) \). This means the sine of the negative angle is the negative of the sine of the positive angle.
Since \( \theta \) is in the second quadrant, \( \sin(\theta) \) is positive (because sine is positive in the second quadrant).
Therefore, \( \sin(-\theta) = -\sin(\theta) \) is negative, because it is the negative of a positive value.

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