Find sinθ.cos (-θ) = (√3)/6, cot θ \u003c 0

Recall the even-odd properties of trigonometric functions: since cosine is an even function, we have $$\cos(-\theta) = \cos(\theta). $$Therefore, $$\cos(\theta) = \frac{\sqrt{3}}{6}. $$Identify the quadrant where $$\theta$$ lies using the given condition $$\cot \theta \u003c 0. $$Since $$\cot \theta = \frac{\cos \theta}{\sin \theta}$$, for $$\cot \theta to be $$negative, sine and cosine must have opposite signs. Given that $$\cos \theta = \frac{\sqrt{3}}{6} is $$positive, and $$\cot \theta \u003c 0$$, it follows that $$\sin \theta$$ must be negative. This places $$\theta in $$the fourth quadrant, where cosine is positive and sine is negative. Use the Pythagorean identity to find $$\sin \theta$$: $$\sin^2$ \theta + \cos^2$ \theta = 1. $$Substitute $$\cos \theta = \frac{\sqrt{3}}{6}$$ and solve for $$\sin^2$ \theta. $$Take the square root of $$\sin^2$ \theta to $$find $$\sin \theta. $$Since $$\sin \theta is $$negative in the fourth quadrant, choose the negative root to determine $$\sin \theta.$$

Ch. 5 - Trigonometric Identities

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Lial 12th Edition

Ch. 5 - Trigonometric Identities

Problema 5.1.16

Capitolo 6, Problema 5.1.16

Find sinθ.
cos (-θ) = (√3)/6, cot θ < 0

Guida verificata passo dopo passo

Recall the even-odd properties of trigonometric functions: since cosine is an even function, we have $\cos(-\theta) = \cos(\theta)$. Therefore, $\cos(\theta) = \frac{\sqrt{3}}{6}$.

Identify the quadrant where $\theta$ lies using the given condition $\cot \theta < 0$. Since $\cot \theta = \frac{\cos \theta}{\sin \theta}$, for $\cot \theta$ to be negative, sine and cosine must have opposite signs.

Given that $\cos \theta = \frac{\sqrt{3}}{6}$ is positive, and $\cot \theta < 0$, it follows that $\sin \theta$ must be negative. This places $\theta$ in the fourth quadrant, where cosine is positive and sine is negative.

Use the Pythagorean identity to find $\sin \theta$: $\sin^2 \theta + \cos^2 \theta = 1$. Substitute $\cos \theta = \frac{\sqrt{3}}{6}$ and solve for $\sin^2 \theta$.

Take the square root of $\sin^2 \theta$ to find $\sin \theta$. Since $\sin \theta$ is negative in the fourth quadrant, choose the negative root to determine $\sin \theta$.

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Even and Odd Properties of Trigonometric Functions

Cosine is an even function, meaning cos(-θ) = cos(θ). This property allows us to replace cos(-θ) with cos(θ) when solving for θ, simplifying the problem by focusing on positive angle values.

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Even and Odd Identities

Sign of Trigonometric Functions in Quadrants

The sign of trigonometric functions depends on the quadrant of the angle. Since cotangent is negative, θ lies in either the second or fourth quadrant, where sine and cosine have specific positive or negative values that help determine the correct angle.

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Quadratic Formula

Relationship Between Cotangent, Sine, and Cosine

Cotangent is the ratio of cosine to sine (cot θ = cos θ / sin θ). Knowing cot θ < 0 helps infer the signs of sine and cosine, which is essential to find the correct value of sin θ consistent with the given conditions.

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5:05

Amplitude and Reflection of Sine and Cosine

Pratica correlata

Domanda del libro di testo

Write each expression in terms of sine and cosine, and then simplify the expression so that no quotients appear and all functions are of θ only. See Example 3.

csc θ cos θ tan θ

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Domanda del libro di testo

Identify the basic trigonometric function graphed, and determine whether it is even or odd.

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Domanda del libro di testo

Verify that each equation is an identity.

(1 + sin θ)/(1 - sin θ) - (1 - sin θ)/( 1 + sin θ) = 4 tan θ sec θ

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