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Ch. 5 - Trigonometric Identities
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 6, Problema 5.1.18

Find sinθ.
tan θ = -(√7)/2, sec θ > 0

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Identify the given information: \( \tan \theta = -\frac{\sqrt{7}}{2} \) and \( \sec \theta > 0 \). Recall that \( \sec \theta = \frac{1}{\cos \theta} \), so \( \sec \theta > 0 \) means \( \cos \theta > 0 \).
Determine the quadrant where \( \theta \) lies. Since \( \tan \theta \) is negative and \( \cos \theta \) is positive, \( \theta \) must be in the fourth quadrant (where cosine is positive and tangent is negative).
Use the identity relating tangent and sine and cosine: \( \tan \theta = \frac{\sin \theta}{\cos \theta} \). Let \( \cos \theta = x \), then \( \sin \theta = \tan \theta \times x = -\frac{\sqrt{7}}{2} x \).
Apply the Pythagorean identity: \( \sin^2 \theta + \cos^2 \theta = 1 \). Substitute \( \sin \theta = -\frac{\sqrt{7}}{2} x \) and \( \cos \theta = x \) to get \( \left(-\frac{\sqrt{7}}{2} x\right)^2 + x^2 = 1 \).
Solve the equation for \( x \) (which is \( \cos \theta \)), then use \( \sin \theta = -\frac{\sqrt{7}}{2} x \) to find \( \sin \theta \). Remember to choose the sign of \( \sin \theta \) consistent with the quadrant (fourth quadrant means \( \sin \theta < 0 \)).

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