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Ch. 6 - Inverse Circular Functions and Trigonometric Equations
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 39

Solve each equation for exact solutions.
sin⁻¹ x - tan⁻¹ 1 = -π/4

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1
Recognize that the equation is given as \(\sin^{-1} x - \tan^{-1} 1 = -\frac{\pi}{4}\), where \(\sin^{-1} x\) and \(\tan^{-1} 1\) are inverse trigonometric functions (arcsine and arctangent respectively).
Recall the exact value of \(\tan^{-1} 1\). Since \(\tan \frac{\pi}{4} = 1\), it follows that \(\tan^{-1} 1 = \frac{\pi}{4}\).
Substitute \(\tan^{-1} 1 = \frac{\pi}{4}\) into the equation to get \(\sin^{-1} x - \frac{\pi}{4} = -\frac{\pi}{4}\).
Add \(\frac{\pi}{4}\) to both sides to isolate \(\sin^{-1} x\): \(\sin^{-1} x = -\frac{\pi}{4} + \frac{\pi}{4} = 0\).
Use the definition of the inverse sine function to solve for \(x\): since \(\sin^{-1} x = 0\), then \(x = \sin 0\). Recall that \(\sin 0 = 0\), so \(x = 0\).

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