Ch. 6 - Inverse Circular Functions and Trigonometric Equations

Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo

Lial 12th Edition

Ch. 6 - Inverse Circular Functions and Trigonometric Equations

Problema 6.2.39

Capitolo 7, Problema 6.2.39

Solve each equation over the interval [0°, 360°). Write solutions as exact values or to the nearest tenth, as appropriate.
9 sin² θ ― 6 sin² θ = 1

Guida verificata passo dopo passo

Start by simplifying the given equation: \(9 \sin^{2} \theta - 6 \sin^{2} \theta = 1\). Combine like terms on the left side to get a simpler expression.

After simplification, you will have an equation in terms of \(\sin^{2} \theta\). Isolate \(\sin^{2} \theta\) by dividing both sides of the equation by the coefficient of \(\sin^{2} \theta\).

Once you have \(\sin^{2} \theta = k\) (where \(k\) is a constant), take the square root of both sides to solve for \(\sin \theta\). Remember to consider both the positive and negative roots because \(\sin \theta\) can be positive or negative in the interval \([0^\circ, 360^\circ)\).

Use the inverse sine function to find the reference angle(s) corresponding to the values of \(\sin \theta\). This will give you the principal solutions.

Determine all solutions for \(\theta\) in the interval \([0^\circ, 360^\circ)\) by considering the signs of \(\sin \theta\) in the four quadrants and using the reference angles found in the previous step.

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Trigonometric Equations

Trigonometric equations involve functions like sine, cosine, and tangent. Solving these equations means finding all angle values within a given interval that satisfy the equation. Understanding how to manipulate and simplify these equations is essential for finding exact or approximate solutions.

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Pythagorean Identity

The Pythagorean identity states that sin²θ + cos²θ = 1 for any angle θ. This fundamental relationship allows substitution between sine and cosine terms, helping to simplify or transform equations involving squared trigonometric functions.

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Interval and Solution Representation

When solving trigonometric equations over a specific interval, such as [0°, 360°), it is important to find all solutions within that range. Solutions can be expressed as exact values (like fractions of π or special angles) or decimal approximations rounded to a specified precision.

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Inverse Sine

Pratica correlata

Domanda del libro di testo

Solve each equation (x in radians and θ in degrees) for all exact solutions where appropriate. Round approximate answers in radians to four decimal places and approximate answers in degrees to the nearest tenth. Write answers using the least possible nonnegative angle measures.

sin x (3 sin x - 1) = 1

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Domanda del libro di testo

Solve for exact solutions over the interval [0°, 360°).

sin θ/2 = -√3/2

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cos θ/2 = 1

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Solve each equation in x over the interval [0, 2π) and each equation in θ over the interval [0°, 360°). Give exact solutions.

sin x = sin 2x