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Ch. 7 - Applications of Trigonometry and Vectors
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 33

Without using the law of sines, explain why no triangle ABC can exist that satisfies A = 103° 20', a = 14.6 ft, b = 20.4 ft.

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1
Recall that in any triangle, the sum of the interior angles must be exactly 180°.
Given angle \(A = 103° 20'\) (which is an obtuse angle), note that the other two angles, \(B\) and \(C\), must sum to \(180° - 103° 20' = 76° 40'\).
Since side \(a\) is opposite angle \(A\), and side \(b\) is opposite angle \(B\), consider the relationship between sides and angles: the larger side is opposite the larger angle.
Here, side \(b = 20.4\) ft is longer than side \(a = 14.6\) ft, so angle \(B\) should be larger than angle \(A\) if the triangle exists, but angle \(A\) is already greater than 90°, making it the largest angle.
This contradiction shows that no triangle can exist with \(A = 103° 20'\), \(a = 14.6\) ft, and \(b = 20.4\) ft, because the side lengths and angle measures are inconsistent with the triangle inequality and angle-side relationships.

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