뒤로BIO 120 Study Guide: Membranes and Enzymes (General Biology)
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Q1. Explain how cholesterol affects membrane fluidity (how does it act as a “fluid buffer”)?
Background
Topic: Cell Membrane Structure and Function
This question tests your understanding of how cholesterol influences the physical properties of the cell membrane, especially its fluidity under different temperature conditions.
Key Terms:
Cholesterol
Membrane fluidity
Phospholipid packing
Step-by-Step Guidance
Recall that cell membranes are composed mainly of phospholipids, which can move and pack together differently depending on temperature.
Consider how cholesterol interacts with phospholipids: it inserts itself between them, affecting their movement.
At moderate (normal) temperatures, cholesterol restricts phospholipid movement, making the membrane less fluid.
At low temperatures, cholesterol prevents phospholipids from packing too tightly, which helps keep the membrane from solidifying.
Try solving on your own before revealing the answer!
Final Answer:
Cholesterol acts as a "fluid buffer" by reducing membrane fluidity at moderate temperatures (restricting phospholipid movement), but at low temperatures, it prevents the membrane from solidifying by disrupting tight packing of phospholipids. This dual action helps maintain membrane flexibility across a range of temperatures.
Q2. How do unsaturated fatty acids increase membrane fluidity at lower temperatures?
Background
Topic: Lipid Structure and Membrane Fluidity
This question tests your knowledge of how the structure of fatty acids affects the physical properties of cell membranes.
Key Terms:
Unsaturated fatty acids
Hydrocarbon tails
Membrane fluidity
Step-by-Step Guidance
Recall that unsaturated fatty acids have one or more double bonds in their hydrocarbon tails, causing kinks.
These kinks prevent the fatty acids from packing closely together.
At lower temperatures, tight packing would normally cause the membrane to solidify.
Unsaturated fatty acids disrupt this packing, keeping the membrane more fluid.
Try solving on your own before revealing the answer!
Final Answer:
Unsaturated fatty acids increase membrane fluidity at lower temperatures by preventing tight packing of phospholipids due to their kinked hydrocarbon tails, which helps keep the membrane flexible and prevents solidification.
Q3. What is carbohydrates' main function in the cell membrane?
Background
Topic: Cell Membrane Components
This question tests your understanding of the role of carbohydrates attached to the cell membrane.
Key Terms:
Cell-to-cell recognition
Immune response
Glycoproteins and glycolipids
Step-by-Step Guidance
Recall that carbohydrates are found on the extracellular surface of the plasma membrane.
Think about how cells use these carbohydrates to identify and interact with each other.
Consider the importance of cell-to-cell recognition in processes like immune response.
Carbohydrates are often attached to proteins (glycoproteins) or lipids (glycolipids).
Try solving on your own before revealing the answer!
Final Answer:
The main function of carbohydrates in the cell membrane is cell-to-cell recognition, allowing cells to distinguish neighboring cells and facilitating immune responses by binding to molecules on the membrane's extracellular surface.
Q4. What is the difference between passive and active transport?
Background
Topic: Membrane Transport Mechanisms
This question tests your understanding of how substances move across cell membranes, and the energy requirements for each process.
Key Terms:
Passive transport
Active transport
Concentration gradient
Carrier proteins
ATP (energy)
Step-by-Step Guidance
Recall that passive transport moves substances down their concentration gradient, requiring no energy.
Passive transport can involve simple diffusion or facilitated diffusion (using channel or carrier proteins).
Active transport moves substances against their concentration gradient, requiring energy (usually ATP).
Active transport is mediated by carrier proteins that change shape to move substances across the membrane.
Try solving on your own before revealing the answer!
Final Answer:
Passive transport moves substances down their concentration gradient without energy, while active transport moves substances against their gradient and requires energy, typically mediated by carrier proteins.
Q5. What would happen to an animal cell if placed in a:
Background
Topic: Osmosis and Cell Membrane Permeability
This question tests your understanding of how different solutions affect animal cells through osmosis.
Key Terms:
Hypotonic solution
Isotonic solution
Hypertonic solution
Osmosis
Step-by-Step Guidance
Recall that a hypotonic solution has a lower solute concentration than the cell, causing water to enter the cell.
In an isotonic solution, solute concentrations are equal inside and outside the cell, so water moves in and out at equal rates.
A hypertonic solution has a higher solute concentration than the cell, causing water to leave the cell.
Think about the consequences for the cell in each scenario: swelling, stability, or shrinking.
Try solving on your own before revealing the answer!
Final Answer:
Hypotonic: The cell swells and may burst (lyse). Isotonic: The cell remains stable with no net water movement. Hypertonic: The cell shrivels and may die. Optimal solution for animal cells: Isotonic.
Q6. What would happen to a plant cell if placed in a:
Background
Topic: Osmosis in Plant Cells
This question tests your understanding of how plant cells respond to different osmotic environments, considering the presence of a cell wall.
Key Terms:
Hypotonic solution
Isotonic solution
Hypertonic solution
Cell wall
Osmosis
Step-by-Step Guidance
Recall that plant cells have a rigid cell wall that helps maintain their shape.
In a hypotonic solution, water enters the cell, but the cell wall prevents bursting, resulting in turgor pressure.
In an isotonic solution, there is no net water movement, and the cell becomes flaccid (wilts).
In a hypertonic solution, water leaves the cell, causing it to shrink away from the cell wall (plasmolysis).
Try solving on your own before revealing the answer!
Final Answer:
Hypotonic: The cell becomes turgid (optimal for plant cells). Isotonic: The cell becomes flaccid and wilts. Hypertonic: The cell shrinks (plasmolysis). Optimal solution for plant cells: Hypotonic.
Q7. What is the difference between integral and peripheral membrane proteins?
Background
Topic: Membrane Protein Structure
This question tests your understanding of the types of proteins found in the cell membrane and their locations.
Key Terms:
Integral proteins
Peripheral proteins
Lipid bilayer
Step-by-Step Guidance
Recall that integral proteins are embedded within the lipid bilayer, often spanning the membrane.
Peripheral proteins are attached to the membrane surface or to integral proteins, but do not penetrate the bilayer.
Think about how these locations affect their functions (e.g., transport, signaling).
Try solving on your own before revealing the answer!
Final Answer:
Integral proteins are embedded in the lipid bilayer, while peripheral proteins are loosely attached to the membrane surface or to integral proteins and do not penetrate the bilayer.
Q8. Arrange the following molecules in order of their likelihood to diffuse across the membrane, from most to least readily: small nonpolar molecules, large polar molecules, small polar molecules, ions. Provide an example of each.
Background
Topic: Membrane Permeability
This question tests your understanding of which types of molecules can cross the cell membrane easily and which cannot.
Key Terms:
Diffusion
Polarity
Size
Examples: CO2 (small nonpolar), glucose (large polar), H2O (small polar), Na+ (ion)
Step-by-Step Guidance
Recall that small nonpolar molecules can diffuse most easily through the lipid bilayer.
Small polar molecules can cross, but less readily than nonpolar molecules.
Large polar molecules have difficulty crossing without transport proteins.
Ions are the least likely to diffuse due to their charge.
Arrange the examples in order based on these properties.
Try solving on your own before revealing the answer!
Final Answer:
Most readily: small nonpolar molecules (e.g., CO2) small polar molecules (e.g., H2O) large polar molecules (e.g., glucose) ions (e.g., Na+) Least readily: ions
Q9. Describe the difference between pinocytosis and receptor-mediated endocytosis.
Background
Topic: Cellular Transport Mechanisms
This question tests your understanding of two types of endocytosis used by cells to take in substances.
Key Terms:
Pinocytosis
Receptor-mediated endocytosis
Vesicle formation
Specificity
Step-by-Step Guidance
Recall that pinocytosis is a non-specific uptake of extracellular fluid and dissolved solutes.
Receptor-mediated endocytosis is a specific process where receptors bind to particular molecules before vesicle formation.
Think about how specificity affects the efficiency and selectivity of these processes.
Try solving on your own before revealing the answer!
Final Answer:
Pinocytosis is non-specific uptake of extracellular fluid, while receptor-mediated endocytosis is specific, involving receptors that bind to particular molecules before vesicle formation.
Q10. Explain the difference between an anabolic pathway and a catabolic pathway. Provide an example of each and include whether each is exergonic or endergonic.
Background
Topic: Metabolic Pathways
This question tests your understanding of the two main types of metabolic pathways and their energy profiles.
Key Terms:
Anabolic pathway
Catabolic pathway
Exergonic
Endergonic
Examples: protein synthesis, cellular respiration
Step-by-Step Guidance
Recall that anabolic pathways build complex molecules from simpler ones and require energy (endergonic).
Catabolic pathways break down complex molecules into simpler ones and release energy (exergonic).
Think of examples: protein synthesis (anabolic), cellular respiration (catabolic).
Consider whether each pathway is spontaneous or nonspontaneous.
Try solving on your own before revealing the answer!
Final Answer:
Anabolic pathways are endergonic and nonspontaneous, requiring energy to build complex molecules (e.g., protein synthesis). Catabolic pathways are exergonic and spontaneous, releasing energy as they break down molecules (e.g., cellular respiration).
Q11. Fill in the following table for exergonic and endergonic reactions:
Background
Topic: Thermodynamics in Biology
This question tests your understanding of the properties of exergonic and endergonic reactions, including spontaneity, free energy change (), and energy absorption/release.
Key Terms and Formulas:
Exergonic reaction: spontaneous, negative, energy released
Endergonic reaction: nonspontaneous, positive, energy absorbed
(Gibbs free energy change)
Step-by-Step Guidance
Recall that exergonic reactions release energy and are spontaneous.
Endergonic reactions absorb energy and are nonspontaneous.
For exergonic reactions, is negative; for endergonic, $\Delta G$ is positive.
Fill in the table with these properties for each reaction type.
Try solving on your own before revealing the answer!
Final Answer:
Type of Reaction | Spontaneous? | Free Energy | |
|---|---|---|---|
Exergonic | Spontaneous | Negative | Released |
Endergonic | Nonspontaneous | Positive | Absorbed |
Q12. How do enzymes speed up the rate of a reaction?
Background
Topic: Enzyme Function
This question tests your understanding of how enzymes act as biological catalysts.
Key Terms:
Enzyme
Activation energy
Catalyst
Step-by-Step Guidance
Recall that enzymes are proteins that catalyze chemical reactions.
Enzymes lower the activation energy required for a reaction to occur.
Lowering activation energy increases the rate at which reactants are converted to products.
Enzymes do not change the overall free energy change () of the reaction.
Try solving on your own before revealing the answer!
Final Answer:
Enzymes speed up reactions by lowering the activation energy barrier, allowing reactions to proceed faster without altering the overall free energy change.
Q13. Describe the difference between a noncompetitive and a competitive inhibitor.
Background
Topic: Enzyme Regulation
This question tests your understanding of how inhibitors affect enzyme activity.
Key Terms:
Competitive inhibitor
Noncompetitive inhibitor
Active site
Allosteric site
Step-by-Step Guidance
Recall that competitive inhibitors bind to the enzyme's active site, blocking substrate binding.
Noncompetitive inhibitors bind to a different site (allosteric site), changing the enzyme's shape and reducing activity.
Think about how each type of inhibitor affects the enzyme's function and substrate binding.
Try solving on your own before revealing the answer!
Final Answer:
Competitive inhibitors bind to the active site and compete with the substrate, while noncompetitive inhibitors bind elsewhere, changing the enzyme's shape and reducing activity without directly competing for the active site.
Q14. Draw a graph predicting the rate of reaction for a lysosomal enzyme as a function of pH. Label the optimal pH on the graph, assuming it matches the enzyme's environment (pH = 4.5).
Background
Topic: Enzyme Activity and Environmental Conditions
This question tests your understanding of how pH affects enzyme activity, especially for enzymes in acidic environments like lysosomes.
Key Terms:
Optimal pH
Enzyme activity
Lysosome
Step-by-Step Guidance
Recall that each enzyme has an optimal pH where its activity is highest.
Lysosomal enzymes function best at acidic pH (~4.5).
Draw a graph with pH on the x-axis and rate of reaction on the y-axis.
Mark the peak of the curve at pH 4.5, indicating optimal activity.
Try solving on your own before revealing the answer!
Final Answer:
The graph should show a bell-shaped curve with the highest rate of reaction at pH 4.5. Activity decreases at pH values above and below 4.5. Label pH 4.5 as the optimal pH.
Q15. How does allosteric regulation work?
Background
Topic: Enzyme Regulation
This question tests your understanding of how enzymes can be regulated by molecules binding at sites other than the active site.
Key Terms:
Allosteric regulation
Allosteric site
Feedback inhibition
Activator
Step-by-Step Guidance
Recall that allosteric regulation involves a regulatory molecule binding to a site other than the enzyme's active site.
This binding can change the enzyme's shape, affecting its activity (either inhibiting or stimulating).
Feedback inhibition is a form of allosteric regulation where the end product of a pathway inhibits an enzyme early in the pathway.
Activators can also bind allosterically to increase enzyme activity.
Try solving on your own before revealing the answer!
Final Answer:
Allosteric regulation works by a regulatory molecule binding to an allosteric site on an enzyme, causing a conformational change that alters the enzyme's activity. This can result in inhibition (feedback inhibition) or activation, depending on the molecule.