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Question

Calculate the critical points for the function p(x)=2x4−16x2+32p(x) = $$2x^4$$ - $$16x^2 + 32 on $$the interval [−2,3][-2, 3]. Identify the absolute maximum and minimum values.

Accepted Answer

Critical points: ﻿x={−2,0,2}x=\left\lbrace-2,0,2\right\rbracex={−2,0,2}﻿﻿pmin⁡(−2)=0p_{\min}\left(-2\right)=0pmin​(−2)=0﻿ and ﻿pmin⁡(2)=0p_{\min}\left(2\right)=0pmin​(2)=0﻿﻿pmax⁡(3)=50p_{\max}\left(3\right)=50pmax​(3)=50﻿

Answer

Critical points: ﻿x={−2,0,2}x=\left\lbrace-2,0,2\right\rbracex={−2,0,2}﻿﻿pmin⁡(−2)=0p_{\min}\left(-2\right)=0pmin​(−2)=0﻿ and ﻿pmin⁡(2)=0p_{\min}\left(2\right)=0pmin​(2)=0﻿pmax⁡(0)=50p_{\max}\left(0\right)=50

Answer

Critical points: ﻿x={−2,0,2}x=\left\lbrace-2,0,2\right\rbracex={−2,0,2}﻿﻿pmin⁡(−2)=0p_{\min}\left(-2\right)=0pmin​(−2)=0﻿﻿pmin⁡(2)=0p_{\min}\left(2\right)=0pmin​(2)=0﻿pmax⁡(2)=50p_{\max}\left(2\right)=50

Answer

Critical points: x={−2,2}x=\left\lbrace-2,2\right\rbrace﻿pmin⁡(−2)=0p_{\min}\left(-2\right)=0pmin​(−2)=0﻿ and ﻿pmin⁡(2)=0p_{\min}\left(2\right)=0pmin​(2)=0﻿﻿pmax⁡(3)=50p_{\max}\left(3\right)=50pmax​(3)=50﻿

Calculate the critical points for the function p(x)=2x4−16x2+32p(x) = 2x^4 - 16x^2 + 32 on the interval [−2,3][-2, 3]. Identify the absolute maximum and minimum values.

Calculate the critical points for the function $p (x) = 2 x^{4} - 16 x^{2} + 32$ on the interval $open bracket negative 2 comma 3 close bracket$ . Identify the absolute maximum and minimum values.