solve-the-equation-for-cos23x14-cos2-3x-frac14-within-the-interval-x-pi-leq-x-le

Question

Solve the equation cos⁡23x=14\$$cos^23x$$=\frac{1}{4} within the interval −π≤x≤π-\pi\leq x\leq\pi.

Accepted Answer

x=−8π9,−7π9,−5π9,−4π9,−2π9,−π9,π9,2π9,4π9,5π9,7π9,8π9x=-\frac{8\pi}{9},-\frac{7\pi}{9},-\frac{5\pi}{9},-\frac{4\pi}{9},-\frac{2\pi}{9},-\frac{\pi}{9},\frac{\pi}{9},\frac{2\pi}{9},\frac{4\pi}{9},\frac{5\pi}{9},\frac{7\pi}{9},\frac{8\pi}{9}

Answer

x=−7π9,−5π9,−π9,π9,5π9,7π9x=-\frac{7\pi}{9},-\frac{5\pi}{9},-\frac{\pi}{9},\frac{\pi}{9},\frac{5\pi}{9},\frac{7\pi}{9}

Answer

x=−8π9,−4π9,−2π9,2π9,4π9,8π9x=-\frac{8\pi}{9},-\frac{4\pi}{9},-\frac{2\pi}{9},\frac{2\pi}{9},\frac{4\pi}{9},\frac{8\pi}{9}

Answer

x=−8π9,−4π9,−2π9x=-\frac{8\pi}{9},-\frac{4\pi}{9},-\frac{2\pi}{9}

Solve the equation cos23x=14\(\cos\)^23x=\(\frac{1}{4}\) within the interval −π≤x≤π-\(\pi\[\leq\) x\(\leq\]\pi\).

Solve the equation $cosine squared 3 x equals one fourth$ within the interval $- π \leq x \leq π$ .