Q1. Convert 14 mm to its equivalent in meters (m).

Background

Topic: Dimensional Analysis (Unit Conversion)

This question tests your ability to convert between metric units using dimensional analysis.

Key Terms and Formulas:

• 1 meter (m) = 1000 millimeters (mm)

Step-by-Step Guidance

1. Write down the given value: 14 mm.

2. Set up a conversion factor so that millimeters will cancel and meters will remain.

3. Use the relationship: .

4. Multiply 14 mm by the conversion factor .

Try solving on your own before revealing the answer!

Q2. Convert 35 kg to its equivalent in grams (g).

Background

Topic: Dimensional Analysis (Unit Conversion)

This question tests your ability to convert between kilograms and grams.

Key Terms and Formulas:

• 1 kilogram (kg) = 1000 grams (g)

Step-by-Step Guidance

1. Start with the given value: 35 kg.

2. Set up a conversion factor so that kilograms cancel and grams remain.

3. Use the relationship: .

4. Multiply 35 kg by the conversion factor .

Try solving on your own before revealing the answer!

Q3. Convert 57 cm3 to its equivalent in liters (L).

Background

Topic: Dimensional Analysis (Volume Conversion)

This question tests your ability to convert between cubic centimeters and liters.

Key Terms and Formulas:

• 1 liter (L) = 1000 cubic centimeters (cm3)

Step-by-Step Guidance

1. Write the given value: 57 cm3.

2. Set up a conversion factor so that cm3 cancels and liters remain.

3. Use the relationship: .

4. Multiply 57 cm3 by the conversion factor .

Try solving on your own before revealing the answer!

Q4. Convert 1,250 cm to its equivalent in kilometers (km).

Background

Topic: Dimensional Analysis (Length Conversion)

This question tests your ability to convert centimeters to kilometers using multiple conversion steps if needed.

Key Terms and Formulas:

• 1 meter (m) = 100 centimeters (cm)

• 1 kilometer (km) = 1000 meters (m)

Step-by-Step Guidance

1. Start with the given value: 1,250 cm.

2. First, convert centimeters to meters using .

3. Then, convert meters to kilometers using .

4. Set up the two conversion factors and multiply them in sequence: .

Try solving on your own before revealing the answer!

Q5. Convert a speed of 88 m/min to its equivalent in cm/s.

Background

Topic: Dimensional Analysis (Rate Conversion)

This question tests your ability to convert both the numerator and denominator units in a rate (speed).

Key Terms and Formulas:

• 1 meter (m) = 100 centimeters (cm)

• 1 minute (min) = 60 seconds (s)

Step-by-Step Guidance

1. Start with the given speed: 88 m/min.

2. Convert meters to centimeters using .

3. Convert minutes to seconds using .

4. Set up the conversion: .

Try solving on your own before revealing the answer!

Q6. A particle moves through a gas at a speed of 15 km/s. How far will it move in 5.5 s?

Background

Topic: Speed, Distance, and Time Calculations

This question tests your ability to use the relationship between speed, distance, and time.

Key Terms and Formulas:

• Distance = Speed × Time

• Make sure units are consistent (e.g., km and s).

Step-by-Step Guidance

1. Write down the given speed: 15 km/s, and time: 5.5 s.

2. Use the formula: .

3. Multiply the speed by the time: .

4. Check that the units will give you kilometers (km) as the answer.

Try solving on your own before revealing the answer!

Q7. A mole of copper contains atoms. How many atoms are there in 0.525 moles?

Background

Topic: The Mole and Avogadro's Number

This question tests your understanding of the mole concept and how to use Avogadro's number to convert between moles and number of atoms.

Key Terms and Formulas:

• 1 mole = atoms (Avogadro's number)

Step-by-Step Guidance

1. Write the given amount: 0.525 moles.

2. Set up a conversion factor using Avogadro's number: atoms.

3. Multiply 0.525 moles by atoms/mole.

Try solving on your own before revealing the answer!

Q8. The density of lead is 11.3 g/mL. What is the mass of 45 mL of the metal?

Background

Topic: Density Calculations

This question tests your ability to use the density formula to find mass from volume and density.

Key Terms and Formulas:

• Density () =

• Rearranged: mass = density × volume

Step-by-Step Guidance

1. Write the given values: density = 11.3 g/mL, volume = 45 mL.

2. Use the formula: .

3. Multiply the density by the volume: .

4. Check that the units cancel properly to give grams (g).

Try solving on your own before revealing the answer!

Q9. A solution of barium nitrate contains 61.2 g per liter of solution. How many grams of barium nitrate are contained in 2.75 L of this solution?

Background

Topic: Solution Concentration Calculations

This question tests your ability to use concentration (mass/volume) to find the total mass in a given volume.

Key Terms and Formulas:

• Concentration =

• Rearranged: mass = concentration × volume

Step-by-Step Guidance

1. Write the given values: 61.2 g/L, 2.75 L.

2. Use the formula: .

3. Multiply the concentration by the volume: .

4. Check that the units cancel to give grams (g).

Try solving on your own before revealing the answer!

Q10. A sample of seawater contains 0.000245 g of sodium chloride per mL of solution. How much sodium chloride is contained in 50.0 mL of this solution?

Background

Topic: Solution Concentration Calculations

This question tests your ability to use a given concentration to find the total mass in a specific volume.

Key Terms and Formulas:

• Concentration =

• Rearranged: mass = concentration × volume

Step-by-Step Guidance

1. Write the given values: 0.000245 g/mL, 50.0 mL.

2. Use the formula: .

3. Multiply the concentration by the volume: .

4. Check that the units cancel to give grams (g).

Try solving on your own before revealing the answer!