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Stoichiometry Practice: Mole-to-Mass and Mass-to-Mass Calculations

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Q1. If you have 3.59 mol of Fe2O3, how many grams of SO3 can react with it? (Fe2O3 + 3SO3 → Fe2(SO4)3)

Background

Topic: Stoichiometry (Mole-to-Mass Calculations)

This question tests your ability to use a balanced chemical equation to relate moles of one substance to the mass of another using stoichiometric ratios and molar mass.

Key Terms and Formulas:

  • Stoichiometric ratio: The ratio of moles between reactants and products from the balanced equation.

  • Molar mass: The mass (in grams) of one mole of a substance.

Key formula:

Step-by-Step Guidance

  1. Identify the given quantity: mol of .

  2. Write the balanced equation: .

  3. Determine the stoichiometric ratio between and from the equation (1:3).

  4. Calculate the moles of needed using the ratio: .

  5. Set up the calculation to convert moles of to grams using its molar mass. (You will need to look up or calculate the molar mass of $\mathrm{SO_3}$.)

Try solving on your own before revealing the answer!

Final Answer: 431 grams of SO3

First, calculate moles of SO3:

Molar mass of SO3 is .

Multiply moles by molar mass:

So, 431 grams of SO3 can react with 3.59 mol of Fe2O3.

Q2. How many grams of CO2 are produced if 2.09 mol of HCl are reacted according to this balanced chemical equation? (CaCO3 + 2HCl → CaCl2 + CO2 + H2O)

Background

Topic: Stoichiometry (Mole-to-Mass Calculations)

This question tests your ability to use a balanced equation to relate moles of one reactant to the mass of a product.

Key Terms and Formulas:

  • Stoichiometric ratio: The ratio of moles between reactants and products from the balanced equation.

  • Molar mass: The mass (in grams) of one mole of a substance.

Key formula:

Step-by-Step Guidance

  1. Identify the given quantity: mol of .

  2. Write the balanced equation: .

  3. Determine the stoichiometric ratio between and (2:1).

  4. Calculate the moles of produced: .

  5. Set up the calculation to convert moles of to grams using its molar mass. (You will need to look up or calculate the molar mass of $\mathrm{CO_2}$.)

Try solving on your own before revealing the answer!

Final Answer: 46.0 grams of CO2

Moles of CO2:

Molar mass of CO2 is .

Multiply moles by molar mass:

So, 46.0 grams of CO2 are produced.

Q3. How many grams of glucose (C6H12O6) are produced if 17.3 mol of H2O are reacted according to this balanced chemical equation? (6CO2 + 6H2O → 6O2 + C6H12O6)

Background

Topic: Stoichiometry (Mole-to-Mass Calculations)

This question tests your ability to use a balanced equation to relate moles of a reactant to the mass of a product.

Key Terms and Formulas:

  • Stoichiometric ratio: The ratio of moles between reactants and products from the balanced equation.

  • Molar mass: The mass (in grams) of one mole of a substance.

Key formula:

Step-by-Step Guidance

  1. Identify the given quantity: mol of .

  2. Write the balanced equation: .

  3. Determine the stoichiometric ratio between and (6:1).

  4. Calculate the moles of produced: .

  5. Set up the calculation to convert moles of glucose to grams using its molar mass. (You will need to look up or calculate the molar mass of .)

Try solving on your own before revealing the answer!

Final Answer: 519 grams of glucose (C6H12O6)

Moles of glucose:

Molar mass of C6H12O6 is .

Multiply moles by molar mass:

So, 519 grams of glucose are produced.

Q4. How many grams of CaCl2 are produced if 56.6 grams of CaCO3 are reacted according to this balanced chemical equation? (CaCO3 + 2HCl → CaCl2 + CO2 + H2O)

Background

Topic: Stoichiometry (Mass-to-Mass Calculations)

This question tests your ability to convert mass of a reactant to mass of a product using molar mass and stoichiometric ratios.

Key Terms and Formulas:

  • Molar mass: The mass (in grams) of one mole of a substance.

  • Stoichiometric ratio: The ratio of moles between reactants and products from the balanced equation.

Key formula:

Step-by-Step Guidance

  1. Identify the given quantity: g of .

  2. Calculate moles of using its molar mass.

  3. Write the balanced equation: .

  4. Determine the stoichiometric ratio between and (1:1).

  5. Set up the calculation to convert moles of to grams using its molar mass. (You will need to look up or calculate the molar mass of $\mathrm{CaCl_2}$.)

Try solving on your own before revealing the answer!

Final Answer: 63.6 grams of CaCl2

Moles of CaCO3:

Stoichiometric ratio is 1:1, so moles of CaCl2 = 0.566 mol.

Molar mass of CaCl2 is .

Multiply moles by molar mass:

So, 63.6 grams of CaCl2 are produced.

Q5. How many grams of carbon dioxide (CO2) are required to produce 525 g of O2 according to this balanced chemical equation? (6CO2 + 6H2O → 6O2 + C6H12O6)

Background

Topic: Stoichiometry (Mass-to-Mass Calculations)

This question tests your ability to convert mass of a product to mass of a reactant using molar mass and stoichiometric ratios.

Key Terms and Formulas:

  • Molar mass: The mass (in grams) of one mole of a substance.

  • Stoichiometric ratio: The ratio of moles between reactants and products from the balanced equation.

Key formula:

Step-by-Step Guidance

  1. Identify the given quantity: $525\mathrm{O_2}$.

  2. Calculate moles of using its molar mass.

  3. Write the balanced equation: .

  4. Determine the stoichiometric ratio between and (6:6 or 1:1).

  5. Set up the calculation to convert moles of to grams using its molar mass. (You will need to look up or calculate the molar mass of $\mathrm{CO_2}$.)

Try solving on your own before revealing the answer!

Final Answer: 726 grams of CO2

Moles of O2:

Stoichiometric ratio is 1:1, so moles of CO2 = 16.41 mol.

Molar mass of CO2 is .

Multiply moles by molar mass:

So, 726 grams of CO2 are required to produce 525 grams of O2.

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